How Does Charge Affect Electric Field in Spherical Shells?

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SUMMARY

The electric field in spherical shells is determined by the net charge present on the conductor. When the net charge is -Q, the electric field at points outside the shell (r > b) is zero, as confirmed by the discussion referencing the video at 3:00-3:10. The relationship between electric flux and electric field is governed by the equation Flux = E*A = q/ε₀, where ε₀ is the permittivity of free space. This principle applies regardless of whether the charge is -Q or -3Q.

PREREQUISITES
  • Understanding of electric fields and Gauss's Law
  • Familiarity with spherical symmetry in electrostatics
  • Knowledge of the concept of electric flux
  • Basic grasp of conductors and charge distribution
NEXT STEPS
  • Study Gauss's Law and its applications in electrostatics
  • Learn about electric field calculations for different charge distributions
  • Explore the implications of charge on conductors in electrostatic equilibrium
  • Investigate the concept of electric flux and its significance in electromagnetism
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields in relation to spherical conductors.

Hooke's Law
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Homework Statement


What is the electric field if r=a and r=b?
Reference:http://www.youtube.com/watch?v=BcuQ2c_WrMc"

2:11

And what if the net charge is just -Q on the conductor instead of -3Q? Will the electric field at r>b be 0?
Reference: Same video, 3:00-3:10

Homework Equations



Flux = E*A = q/ epsilon0
 
Last edited by a moderator:
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Hello Hooke's_Law.

Yes, then E=0 for r>b .
 

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