How Does Constant Power Affect Object Motion Compared to Constant Force?

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Homework Help Overview

The discussion revolves around comparing the motion of two objects, A and B, where object A is subjected to a constant force and object B is pushed with a force that does work at a constant rate. The objective is to find the ratio of the time taken by both objects to travel a distance while their velocities increase from v to 2v.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations derived for the time taken by both objects and express concerns about eliminating variables such as mass (m) and power (P) from their equations. There is an exploration of how to express the time for object B in terms of distance (s) and velocity (v) to facilitate comparison.

Discussion Status

The discussion is ongoing, with participants actively seeking to clarify their equations and eliminate variables to find a ratio. Some guidance has been offered regarding the number of unknowns in the equations, but no consensus has been reached on the best approach to proceed.

Contextual Notes

Participants are working under the constraints of the problem statement, which involves specific relationships between force, power, and motion, and are trying to navigate the implications of these relationships without additional information.

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Homework Statement


Object A of mass m is pushed with a constant force, another object B of the same mass is pushed with a force that does work at constant rate. Velocity of both objects increase from v to 2v and they move a distance of s. Find the ratio of the time taken by objects A and B to move the distance s


Homework Equations





The Attempt at a Solution


Firstly, for object A
s = 1/2(v + 2v)t
t = 2s/3v

Object B has constant power, so
change in energy = work done = 3/2 mv2
3/2 mv2 = Pt
v = (2Pt/3m)1/2
integrating this term, i get
s = 1/3 (8Pt3/9m)1/2

But how do i eliminate m and p?
 
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gaobo9109 said:
But how do i eliminate m and p?

Hi gaobo9109! :smile:

You really only have two unknowns, t and P/m, in your last two equations. :wink:
 
but time taken for Object A to travel distance s is given by the equation t = 2s/3v. So my second equation for t should also be expressed in term of s and v so that the two equation can be divided to find the ratio. However, I have P and m in the equation instead. How can I express the second equation in term of s and v?
 
Eliminate P/m from these two equations …
gaobo9109 said:
Object B has constant power, so

3/2 mv2 = Pt

s = 1/3 (8Pt3/9m)1/2
 

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