How Does Coulomb's Law Apply to a Charge in the Center of a Square?

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Homework Help Overview

The problem involves four charges arranged at the corners of a square with a fifth charge located at the center. The charges consist of two -5 µC charges and two 2 µC charges, with the central charge being -1 µC. The focus is on determining the net force acting on the central charge due to the surrounding charges.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the net force on the central charge and question whether it would be zero due to the symmetry of the charges at the corners. There is uncertainty about the need for distance measurements to apply Coulomb's Law effectively.

Discussion Status

The discussion is ongoing, with participants clarifying the nature of the question regarding net force versus net charge. Some guidance has been provided regarding the application of Coulomb's Law and the vector nature of forces, but no consensus has been reached on the implications for the central charge.

Contextual Notes

Participants express uncertainty about the distances required for calculations and the implications of the arrangement of charges on the net force experienced by the central charge.

radenm
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Homework Statement



four charges aranged on the corners of a square. a fifth charge is located in the middle of the square. what is the net charge on that charge?
givens: two charges -5uC are placed at opposite corners of the square, two charges 2uC are placed at opposite corners of the square, and the fifth charge is -1uC placed at the middle of the square

Homework Equations



F=K(q1*q2)/r^2

The Attempt at a Solution


i do not know if i can find a distance to use the coulombs law equation.
the answer that i want to say is that there is no force exerted on the fifth charge because the charges at the corners opposite from each other are equal thus giving no exerted force.
 
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Are you asked for the net charge on the middle charge that you list as a given already? Or the net force perhaps?

I note that since the charges on opposite corners are equal and in opposite directions and you are equidistant from them ...
 
it is asking for the net force on the middle charge, and i keep thinking that the net force will be 0 because the charges on opposite corners are of equal direction and magnitude.
i just don't know if there is some law or rule that i am unaware of that will put any force on that middle charge
 
radenm said:
it is asking for the net force on the middle charge, and i keep thinking that the net force will be 0 because the charges on opposite corners are of equal direction and magnitude.
i just don't know if there is some law or rule that i am unaware of that will put any force on that middle charge

Well there is Coulomb's Law that serves to show that very thing. Remember that force is a vector, and the statement of Coulomb's Law includes the vector in the direction between the charges.
 
dont i need the distance for each side to figure out the force generated from each charge?
 
radenm said:
dont i need the distance for each side to figure out the force generated from each charge?

Write out the equations and see what cancels out.
 
thank you very much, your clarification was very helpful! :)
 

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