How Does Coulomb's Law Explain the Movement of a Cobweb?

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SUMMARY

The discussion centers on applying Coulomb's Law to analyze the movement of a dust cobweb influenced by electrostatic forces. The cobweb, modeled as a dust ball with a mass of 2.0 x 10-7 g, is attracted to a wall by another dust ball with a charge of -3.0 x 10-6 C. Participants emphasize the importance of drawing a free-body diagram to identify forces such as tension, gravitational force, and electric force, and they clarify that the final charge on the cobweb can be determined using Coulomb's Law, represented by the equation Fe = K(q1q2/d2).

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Homework Statement


A dust cobweb is drawn from an initial vertical position toward a nearby wall by an electrostatic force. Assume the cobweb to be like a single dust ball of mass 2.0 x 10-7g suspended on a massless string of length 0.42 m connected a horizontal distance of 0.35 m from the wall, as shown below. The tethered dust ball is drawn to the wall by another similar dust ball of opposite charge, -q = -3.0 x 10-6C, as shown.

cobweb.jpg


a) Draw a free-body diagram for the tethered dust ball in its final resting position.

b) Transfer the force information from the free-body diagram to a triangle. (I think they mean a component triangle)

c) What is the final charge on the cobweb?

Homework Equations


Fe = \frac{Kq_{1}q_{2}}{d^{2}}

where Fe is the electric force between two objects
K is Coulomb's constant (9.0 x 109 Nm2/C2)
q1 is object 1's electric charge
q2 is object 2's electric charge
d is the distance between centers of charged objects

The Attempt at a Solution


a) just draw the Normal Force, Force of Gravity, and the Electric force?

b)unsure, but i could figure this out alone

c) Would I just solve for the distance between the two dust balls and then sub that into the equation above, using +q for q1 and -q for q2 and 9.0 x 109 for K?

edit: bah, nevermind that failed. need help for c)
 
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Shilly said:

The Attempt at a Solution


a) just draw the Normal Force, Force of Gravity, and the Electric force?
Instead of "normal force", that should be tension.
c) Would I just solve for the distance between the two dust balls and then sub that into the equation above, using +q for q1 and -q for q2 and 9.0 x 109 for K?
You would use that formula (Coulomb's law) to solve for the magnitude of the electric force in terms of the charges. (In what direction does that force act?) The negative charge is given; the positive charge is unknown--that's what you are trying to solve for. (It's a bit confusing that they called the charges +q and -q. If that were true, you wouldn't need to solve for anything!)

Yes, you'll have to compute the distance between the charges.

Hint: You'll need to analyze both vertical and horizontal force components on the tethered dustball.
 

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