How Does Elevator Motion Affect the Tension in a Suspended Lamp's Wire?

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SUMMARY

The discussion focuses on calculating the tension in a wire suspending a 3.0-kg lamp in various elevator motion scenarios. When the elevator moves downward at a constant speed of 6.0 m/s, the tension is 29.4 N. If the elevator moves upward at 6.0 m/s while decelerating at 2.0 m/s², the tension increases to 35.4 N. Conversely, when the elevator descends at 6.0 m/s and decelerates at 2.0 m/s², the tension decreases to 23.4 N. The calculations utilize Newton's second law (F=ma) to derive these values.

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Homework Statement



A 3.0-kg lamp is suspended by a wire from the ceiling of an elevator. What can you conclude about the
tension in the wire under each of the following circumstances? (Give a numerical result, or a range of possible
numerical results, or if you can’t conclude anything about the tension in the wire, say so explicitly. Justify your
response in each case.)

a. The elevator is moving downward with a constant speed of 6.0 m/s.

b. The elevator is moving upward with speed of 6.0 m/s, and slowing down at a rate of 2.0 m/s/s.

c. The elevator is moving downward with speed of 6.0 m/s, and slowing down at a rate of 2.0 m/s/s. (3 pts)

Homework Equations



F=ma

The Attempt at a Solution



a: ma=Tension-mg
(3kg)(0m/s2)=Tension-(3kg)g
Tension=29.4N

b: ma=Tension-mg
(3kg)(2m/s2)=Tension-(3kg)g
Tension=35.4N

c: ma=Tension-mg
(3kg)(-2m/s2)=Tension-(3kg)g
Tension=23.4N

I'm not sure if I even did this right please check it out!
 
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a looks good, but you got b and c reversed. Draw a FBD, note the direction of the acceleration, and examine the direction of the forces and net forces more closely.
 
Oh yes I got mixed up...Thank you
 

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