How Does f(z) = z + 1/z Map a Circle to an Ellipse?

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SUMMARY

The function f(z) = z + 1/z transforms a circle of radius r ≥ 1 into an ellipse. This transformation can be understood geometrically by analyzing the complex function through the substitution z = re^{i\phi}. By separating the expression into x and y components in terms of cos(φ) and sin(φ), and applying the identity cos²(φ) + sin²(φ) = 1, one can derive the equation of an ellipse from the resulting expressions. This method provides a clear geometric interpretation of the mapping process.

PREREQUISITES
  • Complex analysis fundamentals
  • Understanding of polar coordinates
  • Knowledge of trigonometric identities
  • Familiarity with the geometric properties of ellipses
NEXT STEPS
  • Study the properties of complex functions and their mappings
  • Explore the geometric interpretation of complex transformations
  • Learn about the derivation of conic sections from complex functions
  • Investigate the implications of the transformation for different values of r
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Mathematicians, physics students, and anyone interested in complex analysis and geometric transformations will benefit from this discussion.

joeblow
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How does the function f(z) = z + 1/z take a circle of radius g.t. 1 to an ellipse? How do I think about it geometrically ? (i.e., how should I be able to look at the complex function and tell straight away)
 
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joeblow said:
How does the function f(z) = z + 1/z take a circle of radius g.t. 1 to an ellipse? How do I think about it geometrically ? (i.e., how should I be able to look at the complex function and tell straight away)

I can't see it by just looking at it, but I did manage to prove it by inserting [tex]z=re^{i\phi}[/tex], then finding x and y-components of the expression f(z) in terms of [tex]\cos(\phi)[/tex] and [tex]\sin(\phi)[/tex]. Then I used the relationship [tex]cos^2 + sin^2 = 1[/tex] to find an expression among x and y, which turned out to be the equation for an ellipse, as long as r>=1.
 

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