How Does Field Characteristic Affect Linear Independence?

Click For Summary
SUMMARY

This discussion focuses on the implications of field characteristics on linear independence in vector spaces. Specifically, it establishes that if the characteristic of a field F is not 2, the set T = {v1 + v2, v2 + v3, v1 + v3} remains linearly independent given that S = {v1, v2, v3} is linearly independent. Conversely, if char F = 2, T is not linearly independent. Additionally, it confirms that any nonempty subset of a linearly independent set S is also linearly independent, and if a vector v is not in the span of S, then the union S ∪ {v} is linearly independent.

PREREQUISITES
  • Understanding of linear independence in vector spaces
  • Knowledge of field characteristics, specifically char F
  • Familiarity with vector operations and linear combinations
  • Basic proof techniques in linear algebra, including proof by contradiction
NEXT STEPS
  • Study the implications of field characteristics on linear algebra concepts
  • Learn about proof techniques in linear algebra, especially proof by contradiction
  • Explore the concept of span and its relationship to linear independence
  • Investigate examples of vector spaces over fields with different characteristics
USEFUL FOR

Students of linear algebra, mathematicians, and educators seeking to deepen their understanding of linear independence and field characteristics in vector spaces.

kathrynag
Messages
595
Reaction score
0
I'm trying to finish these linear independence proofs:
3. Let S = {v1, v2, v3} be a linearly independent subset of V and let
T = {v1 + v2, v2 + v3, v1 + v3}.
(a) Show that if char F is not 2, then T is linearly independent.
(b) Show that if char F = 2, then T is not linearly independent.
4. Show that if a subset S of V is linearly independent, then any nonempty subset T of S
is also linearly independent.
5. Show that if a subset S of V is linearly independent and v ∈ V is not in sp(S), then
S ∪ {v} is linearly independent



3. linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
The characteristic is confusing me
Like I want to say we have something like 1+1+...+1=0

4.linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
I know we want a1(v1+v2)+a2(v2+v3)+a3(v1+v3)=0 to imply a1=a2=a3=0
we have a1v1+a1v2+a2v2+a2v3+a3v1+a3v3=0
(a1v1+a2v2+a3v3)+a1v2+a2v3+a3v1=0
a1v2+a2v3+a3v1=0
5.linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
v is not in sp(s), so not a linear combination
so v is not in a1v1+a2v2+a3v3

Any hints would be greatly appreciated
 
Physics news on Phys.org
kathrynag said:
I'm trying to finish these linear independence proofs:
3. Let S = {v1, v2, v3} be a linearly independent subset of V and let
T = {v1 + v2, v2 + v3, v1 + v3}.
(a) Show that if char F is not 2, then T is linearly independent.
(b) Show that if char F = 2, then T is not linearly independent.
4. Show that if a subset S of V is linearly independent, then any nonempty subset T of S
is also linearly independent.
5. Show that if a subset S of V is linearly independent and v ∈ V is not in sp(S), then
S ∪ {v} is linearly independent



3. linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
The characteristic is confusing me
Like I want to say we have something like 1+1+...+1=0
I don't know what F is or what char F is.

I think you might be missing an important point about linear independence. Namely, that if v1, v2, and v3 are linearly dependent, then the equation a1*v1 + a2*v2 + a3*v3 = 0 also has a solution for the scalars of a1 = a2 = a3 = 0. The fine point that many students miss is that if the vectors are linearly independent, then there is only one solution to the equation a1*v1 + a2*v2 + a3*v3 = 0. For linearly dependent vectors, there are also other solutions.

Since I don't know what F or char F are supposed to mean, I would show that the equation c1(v1 + v2) + c2(v2 + v3) + c3(v1 + v3) = 0 has exactly one solution for the three constants, given that v1, v2, and v3 are linearly independent.
kathrynag said:
4.linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
I know we want a1(v1+v2)+a2(v2+v3)+a3(v1+v3)=0 to imply a1=a2=a3=0
we have a1v1+a1v2+a2v2+a2v3+a3v1+a3v3=0
(a1v1+a2v2+a3v3)+a1v2+a2v3+a3v1=0
a1v2+a2v3+a3v1=0
5.linear independent so a1v1+a2v2+a3v3=0 implies a1=a2=a3=0
v is not in sp(s), so not a linear combination
so v is not in a1v1+a2v2+a3v3

Any hints would be greatly appreciated
 
Last edited:
The characteristic of a field is the smallest positive number n where the sum of n 1's is equal to 0.

Let a(v1+v2)+b(v2+v3)+c(v1+v3)=0. Then (a+c)v1+(a+b)v2+(b+c)v3=0. Since v1, v2, and v3 are linearly independent, you must have

a+c = 0
a+b = 0
b+c = 0

Now try to solve those equations, taking into account char F.Based on your work, I think you've completely misunderstood problem 4. Can you elaborate on what you wrote? For both problems 4 and 5, a proof by contradiction is probably the way to go.
 
Last edited:

Similar threads

Replies
15
Views
3K
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
18K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K