Prove Linear Independence of {[w1]s, [w2]s,...,[wk]s} in V

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This discussion focuses on proving the linear independence of the set of vectors {[w1]s, [w2]s,...,[wk]s} in R^n, given that {w1, w2, ..., wk} is a linearly independent set in an n-dimensional vector space V with an ordered basis S. The participants clarify that [wi]s represents the coordinate vector of wi expressed in terms of the basis S. Additionally, the uniqueness of the transition matrix between two ordered bases S and T in V is established, asserting that if two matrices A and B satisfy the same transformation conditions, they must be identical.

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1) Let S be an ordered basis for n-dimensional vector space V. Show that if {w1, w2, ..., wk} is a linearly independent set of vectors in V, then {[w1]s, [w2]s,...,[wk]s} is a linearly independent set of vectors in R^n.

What I got so far is
w1 = a1V1 + a2V2 + ... + anVn
so, [w1]s =
[a1
a2
...
an]

The same thing for w2, [w2]s and wk, [wk]s.
My question how to go from there?

2) Let S and T be two ordered bases of an n-dimensional vector space V. Prove that the transition matrix from T - coordinates to S - coordinates is unique. That is, if A,B belong to Mnn both satisfy A[v]T = [V]S and B[V]T = [v]S for all v belong to V, then A = B.

My approach for this question is that
Let S = {v1, v2, vn}
Let T = {w1, w2, wn}
Av = a1v1+a2v2+...+anvn
v = b1w1+b2w2+...+bnwn
Aa1v1 + Aa2v2+ ... +Aanvn
a1(Av1) + a2(Av2)+...+an(Avn)
= b1w1+b2w2+...+bn(wn)

Am I going the right direction? If no, how should I approach? If yes, how should I move from here?
 
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what does [w1]s mean? w1 written in terms of the ordered basis S?
 
lanedance said:
what does [w1]s mean? w1 written in terms of the ordered basis S?

[w1]s mean the s-coordinate vector of w1? for the second part,yes.
 

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