How does field fringing help satisfy boundary conditions?

[Shreya]

Homework Statement

I know the fringing of magnetic field avoids the violation of Amperes circuital law. Is there a similar reason for fringing of Electric Fields?

Relevant Equations

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Please be kind to help

 

[berkeman]

Homework Statement:: I know the fringing of magnetic field avoids the violation of Amperes circuital law. Is there a similar reason for fringing of Electric Fields?
Relevant Equations:: -

Please be kind to help

Could you give some links to what you are saying about fringing of magnetic fields?

And for the fringing of electric fields, do you mean like at the edges of a parallel plate capacitor?

https://www.physicsforums.com/threads/how-to-treat-the-ideal-plate-capacitor-more-rigorously.966790/

 

[haruspex]

Could you give some links to what you are saying about fringing of magnetic fields?

See Answer 1 at https://physics.stackexchange.com/q...es-law-violated-if-there-are-no-fringe-fields

 

[berkeman]

See Answer 1 at https://physics.stackexchange.com/q...es-law-violated-if-there-are-no-fringe-fields

Oh, thanks @haruspex -- I thought he was asking about something exotic, not the standard stuff.

 

[berkeman]

@Shreya -- can you show the boundary conditions for the geometry that @haruspex posted about magnetic fields at the boundary between high and low $\mu$ interfaces?

And can you extend that to the boundary conditions for charge concentration and the electric field near the edges of a parallel plate capacitor? There are no violations of anything in those situations.

 

[Shreya]

See Answer 1 at https://physics

That's exactly what I meant. I am sorry. I should have been more elaborate. Thanks Haruspex.

 

[Shreya]

boundary conditions

Could you please explain what you meant by boundary conditions?

In the magnetic situation, the violation of amperes law is avoided due to the presence of fringing. In the situation that @haruspex mentioned, if there were no fringing, then the line integral of B[dot]dl is positive while Current enclosed is 0. Fringing avoids this problem by making the line integral of B[dot]dl go to 0.