How Does First-Order Kinetics Affect Reactant Concentration Over Time?

Click For Summary
SUMMARY

The discussion focuses on calculating the concentration of a reactant in a first-order reaction with an initial concentration of 0.75M and a rate constant of 2.75/s after 6.5 seconds. The correct application of the first-order kinetics equation, -kt = ln([A]initial/[A]anytime), is crucial for accurate results. Additionally, the half-life of C-14, which is 5.73 x 10^3 years, is derived using the formula t1/2 = 0.693/k, yielding a rate constant of 1.21 x 10^-4/s. This underlines the limitation of radiocarbon dating to approximately 50,000 years due to the decay rate of C-14.

PREREQUISITES
  • Understanding of first-order kinetics
  • Familiarity with rate constants and their significance
  • Knowledge of half-life calculations
  • Ability to apply integrated rate laws for chemical reactions
NEXT STEPS
  • Study the derivation and application of the first-order rate equation
  • Learn about the implications of half-life in radiocarbon dating
  • Explore the concept of relative abundance in isotopes
  • Investigate advanced applications of first-order kinetics in various chemical processes
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical kinetics, radiocarbon dating, and isotope analysis will benefit from this discussion.

konartist
Messages
47
Reaction score
0

Homework Statement


The initial concentration of reactant in a first-order reaction is 0.75M. The rate constant for the reaction is 2.75/s. What is the concentration (mol/L) of reactant after 6.5s?


Homework Equations



-kt=[A]initial/[A]anytime



The Attempt at a Solution



-(2.75/s)(6.5s)=[0.75M]/[A]@6.5seconds

-17.875/1=0.75M/x; x= -4.20x10^-2; The answer to this problem is not right, but I do not have any idea how to go about it another way.

Problem 2.

The usefulness of radiocarbon dating is limited to 50,000 years. Show mathematically why this is true. (Hint: Remember half life follows first order kinetics. The half life of C-14 is 5.73 x 10^3 years).

Half life formula : t1/2= 0.693/k
Common integrate rate law for first order reactions: ln[A]=-kt + ln[A@ initial]
5.73x10^3 = 0.693/k, k = 1.21x10^-4/s

How would I use k in my integrated formula to prove that the half life is limited to 50,000 years?
 
Physics news on Phys.org
#1. You have the wrong rate equation for a first-order reaction. Look at the rate equation you've used in #2. That's the one you need to use here.

#2. What is (roughly) the relative abundance of C-14 (w.r. to C-12) in the atmosphere? Assume you have a sample that has about 1kg of C. How much of that would have been C-14, when the organism was alive? How much of that C-14 will be present in the sample today (use the rate equation to find this)?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
17K
Replies
6
Views
5K
  • · Replies 131 ·
5
Replies
131
Views
10K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
3
Views
4K