How Does Force Affect Velocity in a One-Dimensional System?

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SUMMARY

The discussion centers on calculating the velocity of a 1.8 kg body under the influence of a force defined by Fx = -6x N, where x is in meters. The initial velocity at x = 3.0 m is given as 8.0 m/s. Participants clarify that the work done on the body can be determined by integrating the force function, leading to the conclusion that the integral of Fx with respect to x represents the total work done on the body.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with calculus, specifically integration
  • Knowledge of work-energy principles in physics
  • Basic understanding of one-dimensional motion
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  • Study the concept of work done by a variable force
  • Learn how to apply the work-energy theorem in one-dimensional systems
  • Explore integration techniques for calculating work from force functions
  • Investigate the relationship between force, mass, and acceleration in dynamic systems
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Students and educators in physics, particularly those focusing on mechanics, as well as anyone interested in understanding the dynamics of one-dimensional motion influenced by variable forces.

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The only force acting on a 1.8 kg body as it moves along the positive x-axis has an x component Fx = - 6x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.0 m/s.



(a) What is the velocity of the body at x = 4.0 m?

(b) At what positive value of x will the body have a velocity of 5.0 m/s?



I think to start off i need to take the integral of Fx=-6xN, which would be -3x^2. But from there I'm a bit confused. It doesn't give the force acting on it, so i don't know how to find the work since W=F*Fx.
 
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brittkub1291 said:
The only force acting on a 1.8 kg body as it moves along the positive x-axis has an x component Fx = - 6x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.0 m/s.
(a) What is the velocity of the body at x = 4.0 m?

(b) At what positive value of x will the body have a velocity of 5.0 m/s?
I think to start off i need to take the integral of Fx=-6xN, which would be -3x^2. But from there I'm a bit confused. It doesn't give the force acting on it, so i don't know how to find the work since W=F*Fx.
The integral you did IS the work.
You did integral of Fx*dx and this is dW . The integral is the total work.

And no, the work is not W=F*Fx.
Fx is the force
 

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