How Does Frequency Affect Impedance in a Parallel RLC Circuit?

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Homework Help Overview

The discussion revolves around calculating the impedance of a parallel RLC circuit consisting of a resistor, capacitor, and inductor at different frequencies. Participants are exploring the relationship between frequency and impedance in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate impedance using admittances in a parallel configuration. They question the order of operations regarding taking the modulus and reciprocal of complex numbers.

Discussion Status

Some participants provide insights into the relationship between complex admittance and impedance, discussing the implications of taking the modulus before or after finding the reciprocal. There is an ongoing exploration of the correct approach to the problem without a definitive consensus yet.

Contextual Notes

Participants are considering the implications of their calculations and the context of their coursework, which may influence how they interpret the results regarding modulus and complex numbers.

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A 1000 ohm resistor, 500 picofarad capacitor, and 2 millihenry inductor are all conducted in parallel. What is the impedance if the frequency is 10 kilocycles per second? 10 megacycles per sec? At what frequency is the absolute value of impedance the greatest?

I know I start by considering admittances since those add in parallel. I will end up with a complex number. Can I take its modulus and then the reciprocal? Or do I take the reciprocal to get impedance and then take the modulus? Or do I take the reciprocal to get impedance and leave it as the complex number?
 
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You have a complex admittance.
The complex impedance is the reciprocal of the complex admittance
"Impedence" and "complex impedance" can be used interchangeably: you'll have to use the context of your classes to decide if the modulus is expected or not (that's how I'd interpret it.)

note; if ##y=a+jb##
then, using ##|z|=|1/y|## (i.e. reciprocal then modulus):$$z=1/y = 1/(a+jb) = (a-jb)/(a^2-b^2)\Rightarrow |z| = \sqrt{a^2+b^2}/(a^2-b^2)$$... something like that - what happens if you do it in the other order (i.e. modulus then reciprocal). Is ##|1/y|=1/|y|##)?

See:
http://en.wikipedia.org/wiki/Electrical_impedance
 
Ahah! I was certainly wrong to think I could do the modulus and then take the reciprocal, that would give something like sqrt(a^2+b^2), and it would ignore the denominator that you got in the modulus of z itself.

So if I were to take the modulus, it should ALWAYS be after I've gotten all the way to the end of the problem in complex numbers?
 
It usually works out simpler that way anyhow.
 

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