- #1

k31453

- 58

- 0

This is my question 1.

and this is my question 2.

in a RLC series circuit show above are replaced following : R=500Ω L=0.4mH and C=100pF

the circuit is connected to the terminals of an ac source with an rms voltage of 1V, and a variable frequency calculate the following

A) resonant frequency

ans: f = 1/2*pi*sqrt(LC)

= 1/(2*pi*sqrt(0.0004 * 100 * 10^-12)

= 795.77 Khz

b) the inductive and capacitive reactance at resonance

ans: XL = 2*pi*f*L

= 2*pi* 795.775*10^3*0.0004

= 2000 ohm

Xc = 1/(2*pi*f*C)

= 1/(2*pi* 795.775*10^3 * 100 * 10^-12)

= 1999.9998 ohm

C) the impedance at resonance

ans : impedence of resonance is resistance of circuit : z = R = 500 ohm

D) the rms current at resonance

ans: I = V/R = 1/500 = 0.002A

E) the rms voltage across each element at resonance

Ans: Vr = IR

= 0.002 * 500

= 1V

VL = IXL

= 0.002 * 2000

= 4V

Vc = IXc

= 0.002 * 1999.99

= 3.99998 V

So am i doing it right?? because

i got another reply that says this :

Last edited by a moderator: