How Does Friction Affect Tension in a Pulley System?

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SUMMARY

The discussion focuses on the relationship between tension and friction in a pulley system involving blocks A, B, and C. Block B rests on block A, with a coefficient of static friction (u_s < 1) between them, while block C is suspended on the other end of a massless string over a frictionless pulley. The key equations derived include T = m_a+b*a - f and T = m_c*g, which relate the tension in the string to the masses and friction involved. The analysis concludes that the maximum mass of block C is contingent on the static friction between blocks A and B, ensuring they move together.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient (u_s)
  • Ability to draw and interpret free-body diagrams
  • Familiarity with basic pulley systems and tension concepts
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  • Study the derivation of tension in pulley systems with friction
  • Learn how to calculate maximum static friction in multi-block systems
  • Explore advanced applications of Newton's laws in dynamic systems
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Hi You guys, my first post on here. I'm having a bit of a hard time getting my head around Tension and friction, so am hoping for a little help, which would be much appreciated!

Homework Statement



Block B rests on block A, which in turn is on a horizontal tabletop. There is no friction between A and the tabletop, but the coefficient of static friction between A and B is u_s < 1. A massless string connects A to a block C. The string passes over a frictionless and massless pulley, and block C is suspended from the other end.
f.jpg


a) draw the free-body diagrams for A+B, B and C, ( if A and B moves together )

b) what is the largest mass C can have so that A and B still slide together when the system is released from rest.?

Homework Equations





The Attempt at a Solution


I've drawn the free body diagrams, and trying to find a expression for m_C. But am a bit stuck. If there had been no friction bewteen A and B, B would have slid of when the system is released, so somehow the friction plays into this.
I also know that T is equal for both A and C.
And that A+B moves along the x-axis and C on the y-axis, whic means there is no a_y for A+B and no a_x for C. As they are connected they both move with the same acceleration, so far so good.

My initial thought is :

T = m_a+b*a - f and
T = w_c ( Newtons 3.law, block c works on the string and the string works on block C)

and from there say
m_a+b*a - f = m_c *g (g=a)

-->

m_a+b - f/g = m_c

am I completely on the wrong track??
 
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The answer must contain [itex]\mu_s[/itex] and the mass of B.

The forces on C are simply the weight mC and the tension upward by the string.

The tension pulls on A and B.

A, B and C must accelerate together as a single mass if B is to remain stationary with respect to A.

What is the friction between B and A? How does that relate to the acceleration of A+B+C.
 

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