- #1

prettykitty

- 8

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Relevant equations

Q=kA(ΔT/L)t

k for Pb is 34.3

k for Cu is 395

My attempt

I set up the equation for the rods in the exact same manner.

Q=(34.3)(1.77e-4)(104/.0150)(1)

Q=(395)(1.77e-4)(104/.0150)(1)

I know what is incorrect about these equations is the area I am using. I took the square cross section to mean diameter, which evidently it is not. The answers given in the text are:

Q=(34.3)(.0151)^2(104/.0150)(1)

Q=(395)(.0151)^2(104/.0150)(1)

How should I interpret square cross section in the future?

To finish this problem I am aware that Qtotal=QPb+QCu

Thanks!