How Does Hooke's Law Help Calculate Spring Length for Weight Drops?

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SUMMARY

This discussion focuses on using Hooke's Law to calculate the appropriate length of a spring for a specific weight drop scenario. The example provided involves a 1 lb weight dropped from a height of 10 feet, with the spring constant determined through experimentation. The key principle is equating gravitational potential energy (mgh) with the potential energy stored in a stretched spring, allowing for precise calculations to prevent the weight from hitting the ground.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Knowledge of gravitational potential energy (mgh)
  • Basic principles of energy conservation
  • Familiarity with experimental physics techniques
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Physics students, engineers, and anyone interested in the practical applications of Hooke's Law and spring mechanics.

cman
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I'm trying to figure out how to determine how long a spring should be to drop a known weight a known length? For example...10 foot drop, 1 lb weight, and I pick up a flexible spring from the hardware store (spring constant to be determined by Hooke's law experimentation), should I not be able to determine how long a spring to cut to just make the 1 lb weight drop to but not hit the floor?...much like a bungee question.
 
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Have you learned about conservation of energy in a physics class? You can equate the gravitational potential energy mgh with the potential energy of a stretched spring.
 

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