How Does Iceberg Buoyancy Relate to Sea Water Density?

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Agent M27
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Homework Statement


An iceberg is floating on sea water such that only 10% of its volume is above the water level. What is the density of sea water expressed in terms of the density of ice.


Homework Equations



[tex]\frac{Vf}{Vi}[/tex] = [tex]\frac{\rho}{\rho}[/tex]

[tex]\rho[/tex]f = density of sea water
[tex]\rho[/tex]i = density of ice

The Attempt at a Solution


I know this is a rather simple problem but where I am getting hung up is the ratio of the visible portion of the iceberg. I hate to admit but the simple maths trip me up. I began by isolating the eq so that:

[tex]\rho[/tex]f = [tex]\rho[/tex]i [tex]\frac{Vi}{Vf}[/tex]

from which I get [tex]\frac{9}{10}[/tex] [tex]\rho[/tex]i


By the way this is an even number problem so I cannot look up the answer, so is this correct?

Thanks in advance.

Joe
 
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Agent M27 said:

Homework Equations



[tex]\frac{Vf}{Vi}[/tex] = [tex]\frac{\rho}{\rho}[/tex]

[tex]\rho[/tex]f = density of sea water
[tex]\rho[/tex]i = density of ice
You left out the subscipts on the ρ terms in your equation.

The Attempt at a Solution


I know this is a rather simple problem but where I am getting hung up is the ratio of the visible portion of the iceberg. I hate to admit but the simple maths trip me up. I began by isolating the eq so that:

[tex]\rho[/tex]f = [tex]\rho[/tex]i [tex]\frac{Vi}{Vf}[/tex]

from which I get [tex]\frac{9}{10}[/tex] [tex]\rho[/tex]i
Think about your answer. It says that the sea water is (more, less?) dense than the ice, and therefore the iceberg should (float, sink?).
 
As you said, It's a very simple problem.

[tex]\rho_{0}V_{0}g=\rho g (V_{0}-V)[/tex]

[tex]\rho_{0}[/tex] and [tex]V_{0}[/tex] are density and volume of the iceberg and [tex]\rho[/tex] is density of water and [tex]V[/tex] is visible volume of the iceberg.

You can easily get the sought ratio.

[tex]\frac{\rho_{0}}{\rho}=\frac{V_{0}-V}{V_{0}}=1-\frac{V}{V_{0}}[/tex]
 
From my answer it says that the sea water is less dense than that of ice, which is actually incorrect when I think about a glass of ice water. So then my answer ought to be:

[tex]\rho[/tex]f = [tex]\frac{10}{9}[/tex] x [tex]\rho[/tex]i

which correctly shows that the sea water is more dense than ice, is this the correct answer?

Thanks redbelly. Also I didn't put the subscripts in the original EQ because I have issues when I apply subs scripts in a fraction for some silly reason.

Joe