Solving Archimedes Principle: 6500kg Iceberg in Sea

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SUMMARY

The discussion focuses on calculating the buoyant force acting on a 6500 kg iceberg with a density of 930 kg/m³ floating in seawater with a density of 1030 kg/m³. The buoyant force is determined using the equation F_B = x_displaced = ρgV, where the forces of gravity and buoyancy are in equilibrium. The solution involves calculating the volume of water displaced and the fraction of the iceberg's volume submerged, confirming that the iceberg remains afloat due to the balance of these forces.

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  • Understanding of buoyancy and Archimedes' Principle
  • Familiarity with density calculations
  • Basic knowledge of equilibrium in physics
  • Ability to apply the formula F_B = ρgV
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  • Calculate the buoyant force on different objects using Archimedes' Principle
  • Explore the relationship between density and buoyancy in various fluids
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Homework Statement


a 6500kg iceberg is afloat in the sea. the icebergs density is 930kg/m^3 and the sea water has density of 1030kg/m^3
a) find the buoyant force on the iceberg
the volume of water displaced and the fraction of the icebergs volume that is below the waterline.


Homework Equations



F_B=x_displaced=rho g V

The Attempt at a Solution


i have no idea how to do this i thought that maybe since its not sinking its in equilibrium relative to something but i have no idea if that's even right or not.. thanks for any help in advance.
 
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You are on the right track. It is pulled down by gravity, and pushed up by buoyancy - these are two forces in equilibrium. One of these is very easy to calculate from the data given - that gives you the other one (they are in equilibrium, which means they are identical).
 
ok thank you i can't believe i missed that - problem solved thanks to you and PF!
 

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