How Small Can the Iceberg Get Before the Polar Bear Gets Wet Feet?

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Homework Help Overview

The problem involves a polar bear floating on an iceberg and seeks to determine the minimum volume of the iceberg before the bear gets wet as the ice melts. The context is rooted in buoyancy principles and fluid mechanics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of buoyant force equations and the relationship between the weight of the bear, the weight of the ice, and the buoyant force. There are questions about the calculations and assumptions made regarding the volume of the iceberg and its buoyancy.

Discussion Status

Some participants express agreement with the initial calculations, while others question the assumptions regarding the iceberg's volume and its full submersion. There is no explicit consensus on the correctness of the approach or the final answer.

Contextual Notes

Participants note potential discrepancies between their calculations and answers provided in textbooks or computer systems, suggesting a need to clarify the assumptions used in the problem setup.

CR9
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Homework Statement


A polar bear of mass 520 kg is floating on an iceberg in the ocean. As the ice melts, how small can the iceberg get before the bear gets wet feet? (The answer should be the volume of the iceberg).


Homework Equations


Buoyant Force, Fb = p(fluid)V g

From a table in my textbook, p(ice)= 920 kg/m^3 and p(sea water)= 1030 kg/m^3



The Attempt at a Solution


I did a sum of the forces in the y-direction to be zero and obtained:

Fb - W(bear) - W(ice)= 0
p(sea water)V = 520 + p(ice)V
V= 4.73 m^3

My answer is wrong... PLease help...
 
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CR9 said:

Homework Statement


A polar bear of mass 520 kg is floating on an iceberg in the ocean. As the ice melts, how small can the iceberg get before the bear gets wet feet? (The answer should be the volume of the iceberg).


Homework Equations


Buoyant Force, Fb = p(fluid)V g

From a table in my textbook, p(ice)= 920 kg/m^3 and p(sea water)= 1030 kg/m^3



The Attempt at a Solution


I did a sum of the forces in the y-direction to be zero and obtained:

Fb - W(bear) - W(ice)= 0
p(sea water)V = 520 + p(ice)V
V= 4.73 m^3

My answer is wrong... PLease help...

I like your answer!
 
I also think your answer is correct.
 
I also am getting your answer: the iceberg is just completely submerged, so you should be using its full volume in the buoyancy force calculation. Is what is telling you this is wrong an answer in the back of a textbook, or a computer problem system?
 

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