oreosama
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A block of ice of mass m is released from rest at the top of a frictionless ramp of length L. at the bottom of the incline the speed of the ice is v1. given m,L,v1 determine
the time needed to hit the bottom
the angle between the ramp and the horizontal
the accel of the ice
I made my coordinate system slant at the angle of the ramp because I thought this would make it less work
http://i.imgur.com/d18GN.png
(is this okay?)
x0 = 0
x = L
v0 = 0
v = v1
a= A
t = T
v1 = 0 + AT
T = v1/A
v1^2 = 2AL
A = v1^2 / 2L
T = v1 / (v1^2 / 2L)
T = 2L / v1
I got these answers pretty cleanly but I have no idea what I should be doing to get theta since I don't see a way to get the lengths of the potential triangle with hypoteneus L
the time needed to hit the bottom
the angle between the ramp and the horizontal
the accel of the ice
I made my coordinate system slant at the angle of the ramp because I thought this would make it less work
http://i.imgur.com/d18GN.png
(is this okay?)
x0 = 0
x = L
v0 = 0
v = v1
a= A
t = T
v1 = 0 + AT
T = v1/A
v1^2 = 2AL
A = v1^2 / 2L
T = v1 / (v1^2 / 2L)
T = 2L / v1
I got these answers pretty cleanly but I have no idea what I should be doing to get theta since I don't see a way to get the lengths of the potential triangle with hypoteneus L