How Does Keplerian Motion Work in 4 Dimensions?

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Homework Help Overview

The discussion revolves around the concept of Keplerian motion in a four-dimensional context, specifically focusing on the properties of a vector (t', x', y', z') and its relation to a sphere. Participants are exploring the implications of energy and mass in this framework, as well as the definitions and meanings of terms used in the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the requirement for the vector to lie on a sphere and the implications of the energy-mass relationship. Questions are raised about the meaning of "sphere" in this context and the significance of the energy being negative. There is also discussion about the scaling of solutions and the relationship between different orbits.

Discussion Status

The discussion is ongoing, with participants seeking clarification on various aspects of the problem. Some have offered insights into the scaling of systems and the nature of orbits, while others are questioning the definitions and assumptions being made. There is no explicit consensus, but productive lines of inquiry are being explored.

Contextual Notes

Participants note the absence of a full problem statement, which is affecting their ability to engage fully with the topic. There are also references to specific definitions and relationships that may not be universally understood, leading to some confusion.

Caneholder123
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This is the link to the relevant paper. I have to show that vector (t', x', y', z') lies on the sphere. But for that to be, V^2 has to be 1 according to the equation in the introductory part of the section 2.

That, by definition, means that E=-m/2. What does that mean, and why is this solution not just a special case?
 
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Caneholder123 said:
I have to show that vector (t', x', y', z') lies on the sphere.
What does "sphere" mean (the elements have a different dimension) and why do you have to show that?

V=1 does not make sense in that context.
 
mfb said:
What does "sphere" mean (the elements have a different dimension) and why do you have to show that?

V=1 does not make sense in that context.

t' is defined in the problem I have to solve as r, and that makes the units in that context OK, but V^2 still remains after calculation is done. John Baez writes about this in his http://blog , and he defines m=1, E=-1/2 and k=1, and that solves the problem. I am not familiar with this procedure, though. He says that he is working with a single fixed energy, but why does this make a general case? I understand that E has to be negative to have the ellipse and that m and k are just scaling factors, but why does it have to be half the mass, and what is the meaning of that altogether?

The point of the problem is to derive from this symmetry the conservation of Runge-Lenz vector.
 
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Caneholder123 said:
the problem I have to solve
Please post the full problem statement, otherwise this is becoming wild guesswork.

Caneholder123 said:
but why does this make a general case?
All other energy values give trajectories that are scaled versions of this.

Caneholder123 said:
but why does it have to be half the mass
I'm quite sure it does not, but without problem statement it is hard to tell. It is convenient to consider this energy for sure because the factors of V go away.
 
mfb said:
Please post the full problem statement, otherwise this is becoming wild guesswork.

Starting from the equations of motion, show that the "vector of speed" of particle \vec V = (t', \vec r') (where the symbol ' is used for differentiation in respect to s) lies on the 4D sphere. Determine the center and radius of that sphere. s is defined with the following relation \frac {ds}{dt} = \frac 1r.

EDIT: I am translating this, and there are no different words for speed and velocity in my mother tongue, so the syntagma "vector of speed" may sound a little bit weird.
 
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An odd sphere, but you can always scale the system to make it spherical. Yes, then V=1 and the energy/mass relation you posted is satisfied. The general solutions are then scaled version of this special case.
 
mfb said:
An odd sphere, but you can always scale the system to make it spherical. Yes, then V=1 and the energy/mass relation you posted is satisfied. The general solutions are then scaled version of this special case.

This kind of thinking is new to me. I am not sure that I completely understand this, probably because I am stuck with kgs and Joules. Does this mean that we fix mass to some value, let's say 10 of something and then we define energy to be -20*m*(some unit speed squared)?
 
It is sufficient to fix the ratio, but that is the idea.

There is no fundamental difference between orbits like the one of Mercury and orbits similar to Neptune, for example. They have the same possible shapes. One is just larger.
 
mfb said:
It is sufficient to fix the ratio, but that is the idea.

There is no fundamental difference between orbits like the one of Mercury and orbits similar to Neptune, for example. They have the same possible shapes. One is just larger.

Thank you very much for the help!
 

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