How Does Newton's Second Law Apply to Tug of War on Ice?

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    Grade 11 Physics
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SUMMARY

The discussion centers on applying Newton's Second Law to a tug of war scenario on a frictionless icy surface. Pete, weighing 539 N, exerts a force on John, who weighs 392 N and accelerates towards Pete at 3 m/s². Using the formula F = ma, the force exerted by Pete on John is calculated to be 1176 N. Additionally, Pete's acceleration towards John is determined to be 0.735 m/s².

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Shaley
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pete and john play a game of tug f war on a frictionless icy curface. pete weighs 539 N and john weights 392 N. during the course of the game, john accelerates toward pete at a rate of 3 m/s^2

a)what's the magnitude of the force that peter exerts on john?
b)what's the magnitude of pete's acceleration toward john?

I am not sure what formula to use, pleaase help!
 
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Hi Shaley! :smile:

(try using the X2 tag just above the Reply box :wink:)

For a), what formulas do you know relating acceleration and force? :smile:
 
Use Newton's Second Law.
 

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