How does one find the time dependent wavefunction?

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SUMMARY

The discussion focuses on finding the time-dependent wavefunction, specifically for the wavefunction $$\Psi(x) = N e^{-\mu x}$$ in the context of an infinite square well potential. It is established that this wavefunction does not satisfy the boundary conditions required for the infinite well, as it does not reside within the Hilbert space of the potential. The correct approach involves decomposing the wavefunction into a sum of energy eigenfunctions and applying the time evolution factor $$e^{-iE_{n}t/\hbar}$$ to each term. Alternatively, the Crank-Nicolson method can be utilized for discretizing the time-space domain to solve for the wavefunction.

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Homework Statement


Random given wavefunction,say $$\Psi (x) = N e^{- \mu x}$$ in a V(x) e.g. infinite well .Find ## \Psi (x,t) ##.

Homework Equations


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The Attempt at a Solution


If the wavefunction is given as the sum of eigenfunctions,you just multiply them by ## e^{-i \frac{tE}{\hbar}}##.But in the case above there isn't one defined energy so you can't do this.
 
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Well, first of all, the wavefunction that you proposed is incompatible with the infinite square well as it does not live within the Hilbert space of the infinite square well potential - the boundary conditions clearly don't agree.

That aside, you already recognised that if the wavefunction were to be written in the form of a sum of energy eigenfunctions, then you would simply affix the relevant exponential factor to each term i.e.
\Psi(x,t) = \sum_{n} c_{n} \psi_{n}(x) e^{- iE_{n}t / \hbar}
So then, if you were given an arbitrary wavefunction, the first thing that needs to be done is none other than to decompose it into the sum of the relevant eigenfunctions of the system:
\Psi(x) = \sum_{n} c_{n} \psi_{n}(x) i.e. you need to solve for the coefficients ##c_{n}##.
 
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tumconn said:

Homework Statement


Random given wavefunction,say $$\Psi (x) = N e^{- \mu x}$$ in a V(x) e.g. infinite well .Find ## \Psi (x,t) ##.

Homework Equations


-

The Attempt at a Solution


If the wavefunction is given as the sum of eigenfunctions,you just multiply them by ## e^{-i \frac{tE}{\hbar}}##.But in the case above there isn't one defined energy so you can't do this.

It would have to be ##\psi(x) = Ne^{-\mu |x|}## to be normalizabe, and even then the wavefunction wouldn't be exactly zero outside any interval ##x\in [a,b]## like it has to be in an infinite well.

The options for solving ##\psi (x,t)## are either the decomposition to eigenfunctions of ##H## and multiplication with the ##e^{-iEt}## factors, or discretization of the considered time-space domain ##\psi (m\Delta x, n\Delta t)=\psi_{m,n}## and solution of the numbers ##\psi_{m,n}## with Crank-Nicolson method (this works even if the spectrum of ##H## isn't known).
 
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