How does one find the time dependent wavefunction?

In summary, the wavefunction cannot be written as the sum of eigenfunctions of the system, and solving for the coefficients ##c_{n}## is necessary to obtain a solution for the wavefunction.
  • #1
tumconn
3
0

Homework Statement


Random given wavefunction,say $$\Psi (x) = N e^{- \mu x}$$ in a V(x) e.g. infinite well .Find ## \Psi (x,t) ##.

Homework Equations


-

The Attempt at a Solution


If the wavefunction is given as the sum of eigenfunctions,you just multiply them by ## e^{-i \frac{tE}{\hbar}}##.But in the case above there isn't one defined energy so you can't do this.
 
Physics news on Phys.org
  • #2
Well, first of all, the wavefunction that you proposed is incompatible with the infinite square well as it does not live within the Hilbert space of the infinite square well potential - the boundary conditions clearly don't agree.

That aside, you already recognised that if the wavefunction were to be written in the form of a sum of energy eigenfunctions, then you would simply affix the relevant exponential factor to each term i.e.
[tex]\Psi(x,t) = \sum_{n} c_{n} \psi_{n}(x) e^{- iE_{n}t / \hbar} [/tex]
So then, if you were given an arbitrary wavefunction, the first thing that needs to be done is none other than to decompose it into the sum of the relevant eigenfunctions of the system:
[tex]\Psi(x) = \sum_{n} c_{n} \psi_{n}(x) [/tex] i.e. you need to solve for the coefficients ##c_{n}##.
 
  • Like
Likes tumconn
  • #3
tumconn said:

Homework Statement


Random given wavefunction,say $$\Psi (x) = N e^{- \mu x}$$ in a V(x) e.g. infinite well .Find ## \Psi (x,t) ##.

Homework Equations


-

The Attempt at a Solution


If the wavefunction is given as the sum of eigenfunctions,you just multiply them by ## e^{-i \frac{tE}{\hbar}}##.But in the case above there isn't one defined energy so you can't do this.

It would have to be ##\psi(x) = Ne^{-\mu |x|}## to be normalizabe, and even then the wavefunction wouldn't be exactly zero outside any interval ##x\in [a,b]## like it has to be in an infinite well.

The options for solving ##\psi (x,t)## are either the decomposition to eigenfunctions of ##H## and multiplication with the ##e^{-iEt}## factors, or discretization of the considered time-space domain ##\psi (m\Delta x, n\Delta t)=\psi_{m,n}## and solution of the numbers ##\psi_{m,n}## with Crank-Nicolson method (this works even if the spectrum of ##H## isn't known).
 
  • Like
Likes tumconn

FAQ: How does one find the time dependent wavefunction?

1. What is a time dependent wavefunction?

A time dependent wavefunction is a mathematical representation of the state of a quantum mechanical system that evolves over time.

2. How is the time dependent wavefunction calculated?

The time dependent wavefunction is calculated using the Schrödinger equation, which is a mathematical formula that describes the evolution of a quantum system.

3. Can the time dependent wavefunction be measured?

No, the time dependent wavefunction is a mathematical construct and cannot be directly measured. However, it can be used to make predictions about the behavior of quantum systems.

4. How is the time dependent wavefunction related to the time independent wavefunction?

The time dependent wavefunction is a complex-valued function that depends on both time and position, while the time independent wavefunction is a real-valued function that only depends on position. The time independent wavefunction can be derived from the time dependent wavefunction by separating the time variable.

5. What factors can affect the time dependent wavefunction?

The time dependent wavefunction can be affected by a variety of factors, including the potential energy of the system, the initial conditions of the system, and any external forces or interactions.

Back
Top