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Physics
Classical Physics
Electromagnetism
How does permittivity in Coulomb's law work?
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[QUOTE="Efeguleroglu, post: 6452885, member: 661265"] In a capacitor, for this formula $$ C = \epsilon \frac{A}{d}$$ dielectric constant is calculated using $$ \epsilon_{eff} = \frac{\int\epsilon dV}{V} $$ or in 2D $$ \epsilon_{eff} = \frac{\int\epsilon dA}{A} $$ I know capacitors are full of approximations but there is this formula and I don't know how to use it for a more fundamental level. Maybe this is true: Suppose we have point charges q1 and q2 with a distance L between them. Then, $$\epsilon_{eff} = \frac{\int_0^L \epsilon dx}{L}$$ The magnitude of electric force acting on any of them is $$F= \frac{1}{4 \pi \epsilon_{eff}} \frac{q_1 q_2}{L^2}$$ I am not really sure what I am doing. I'm just assuming arithmetic mean will work in this way. Is this true? [/QUOTE]
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Physics
Classical Physics
Electromagnetism
How does permittivity in Coulomb's law work?
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