How Does Resistance and EMF Affect Energy Transfer in a Circuit?

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SUMMARY

The discussion focuses on calculating energy transfer in a circuit with a resistance of 5.0 Ω connected to a 2.0 V battery with an internal resistance of 1.0 Ω. The current was determined to be 0.333 A using the formula i=E/(R+r). The energy transferred from chemical to electrical form in the battery was calculated to be 80 J. The user initially struggled with the power calculations but resolved the issue independently.

PREREQUISITES
  • Understanding of Ohm's Law and circuit analysis
  • Familiarity with electrical power equations (P=iV, P=i²r)
  • Knowledge of energy transfer concepts in electrical circuits
  • Basic grasp of internal resistance in batteries
NEXT STEPS
  • Study the impact of internal resistance on battery performance
  • Learn advanced circuit analysis techniques using Kirchhoff's laws
  • Explore energy conservation in electrical systems
  • Investigate thermal energy dissipation in resistive components
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Students studying electrical engineering, physics enthusiasts, and anyone interested in understanding energy transfer in electrical circuits.

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Homework Statement



A wire of resistance 5.0 Ω is connected to a battery whose emf ε is 2.0 V and whose internal resistance is 1.0 Ω. In 2.0 min, how much energy is (a) transferred from chemical to electrical form in the battery, (b) dissipated as thermal energy in the wire, and (c) dissipated as thermal energy in the battery?


Homework Equations



P=iV
P=i^2r
P=iE(the fancy E)
Vb-Va=(E/(R+r))R
i=E/(R+r)


The Attempt at a Solution



I am having trouble finding the current, so I cannot find power.
I am using i=2.0V/(5.0+1.0)=0.333A
then I get Vb-Va=(0.333Ax5.0)
the answer for part a) is 80J
when I use P=iV I don't get that answer...

If I could make it more clear...I can, just post!
 
Physics news on Phys.org
nevermind, I figured it out on my own

BOARD CLOSED
 

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