How Does Rolling Friction Affect a Toy Train's Motion on a Circular Track?

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SUMMARY

The discussion focuses on the effects of rolling friction on a toy train's motion on a circular track with a diameter of 1.4 meters and a coefficient of rolling friction of 0.12. The key equations for calculating angular acceleration (α = ω²*r) and tangential acceleration (a = rα) are highlighted. The conversation clarifies that while centripetal forces act on the train due to the track, rolling resistance acts tangentially, causing the train to decelerate. The initial angular speed of the train is 16 rpm, which is essential for determining its motion dynamics.

PREREQUISITES
  • Understanding of angular acceleration and its calculation using α = ω²*r
  • Knowledge of tangential and centripetal acceleration concepts
  • Familiarity with the coefficient of rolling friction and its implications
  • Basic principles of circular motion and forces acting on objects in motion
NEXT STEPS
  • Calculate the angular acceleration of the toy train using the provided equations
  • Determine the time it takes for the train to stop from an angular speed of 16 rpm
  • Explore the differences between tangential and centripetal acceleration in circular motion
  • Investigate the role of rolling resistance in various types of vehicles, including trains and cars
USEFUL FOR

Physics students, educators, and anyone interested in the dynamics of motion, particularly in circular tracks and the effects of friction on moving objects.

popo
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Mentor note: moved to homework section
Hi, thanks for taking a look!

A toy train rolls around a horizontal 1.4-m-diameter track. The coefficient of rolling friction is 0.12.
(a) What is the magnitude of the train's angular acceleration after it is released?
(b) How long does it take the train to stop if it's released with an angular speed of 16 rpm?

I think I know which equations to use: α = ω^2*r and a = rα, but there is no mention of velocity in the problem so I am stuck.
 
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Use Newton's 2nd law to get tangential acceleration. Then your 2nd formula translates it into angular acceleration.
There's a homework help forum a few links up from this one for questions like this.
 
then my question would go to why we use tangential acc instead of centripetal acc?
 
I know we want to find angular acc so we need to use a = rα, which that is tangential acc, but the thing is the train is moving in ciruclar motion so there should only be centripetal forces acting on it which would be the friction.
 
The rolling resistance is not acting as a centripetal force. It is tangential.
 
is that a special case? because from what i learn for circular motion there would be friction force acting centripetally or centrifugally.
 
Yes, but that's not the rolling resistance. The tracks are providing a centripetal force. In the case of a car, it is static friction causing the centripetal acceleration, and rolling resistance causing the car to lose speed. In the case of a train, it is a normal force acting towards the center of the curve that acts as the centripetal force. Rolling resistance just slows it down.
 
Okay now i get you, but just want to be clear that i have the same picture about the train. How does the track looks like? It said horizontally so is that like a circular train on a horizontal flat surface?
 
I appreciate you help by the way
 
  • #10
Yes, horizontal just means flat ground here.
Your welcome!
 
  • #11
popo said:
but there is no mention of velocity

popo said:
it's released with an angular speed of 16 rpm
Angular speed will tell you the tangential velocity if you know the radius of the track.
 

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