How Does Speaker Arrangement Affect Sound Intensity at a Point?

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SUMMARY

The discussion focuses on the effects of speaker arrangement on sound intensity, specifically analyzing three speakers connected to a tone generator. When all speakers are connected, the total intensity at point P, located far along the x-axis, is calculated to be 135 mW/m². The problem also explores the conditions for maximum intensity along the y-axis when the distance a is set to λ/4, prompting inquiries about constructive versus destructive interference in sound waves.

PREREQUISITES
  • Understanding of sound wave properties and intensity calculations
  • Familiarity with the equations I = P/A and P(0) = (2vρI)^(1/2)
  • Knowledge of constructive and destructive interference in wave physics
  • Basic principles of acoustics and speaker arrangement
NEXT STEPS
  • Study the principles of wave interference and its impact on sound intensity
  • Learn about the relationship between amplitude and intensity in sound waves
  • Explore the effects of speaker placement on sound distribution in acoustics
  • Investigate the mathematical modeling of sound intensity in multi-speaker systems
USEFUL FOR

Acoustics engineers, physics students, audio system designers, and anyone interested in optimizing sound intensity through speaker arrangement.

Firben
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Homework Statement


Three speakers with the same effect are connected to the same tone generator are placed along the y-axis and sends out sound in equal directions. The distance a and b are in the same magnitude as the wave length of the sound.

http://s716.photobucket.com/user/Pitoraq/media/Fys21_zps1596efc1.png.html

a)
The point P is located on a distance L >> a from the speakers along the x-axis. If only one speaker is connected the intensity in the point P is 15.0 mW/m^2. Which is the total intensity when all speakers are connected ?

b)
If the distance a = λ/4, which is the smallest distance b that gives maximum intensity along the y-axis from a distance L ?


Homework Equations


I = P/A
P(0) = (2vρI)^(1/2)
I = P(0)/(2vρr^2)


The Attempt at a Solution



I = P/A
ρ = 1.2929 kg/m^2 density of air
P(0) = (2vρI)^(1/2) = 115.5 pa
I = P(0)/(2vρr^2) <==> r = P(0)/(2vρI)^(1/2) = 31.62 m

If r is the distance from the point P to one of the three speakers, i don't know which one. And what do they mean with "The distance a and b are in the same magnitude as the wave length of the sound." ?
 
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The r can be the distance from any of the three speakers since L >> a. Imagine standing 1 Km away from 3 water bottles separated by 1 cm. The distance between you an any of the bottles is practically the same.

An order of magnitude is the power of 10. It just means the distances are almost similar. For example, 1*10^2 and 5*10^2 are in the same order of magnitude; 1*10^3 and 1*10^9 are NOT in the same order of magnitude.
 
I wonder if it should be constructive or destructive interference ?
 
I solved a) but on b) How can i find the maximum intensity on the y-axis, is it destructive interference ? or destructive ?
 
Last edited:
Since the Maximum Intensity of the wave is just the Amplitude squared: I=|A|^2 , we can deduce that the amplitude of the wave coming out of one speaker is ##\sqrt{15m}##. We also know that the Total Maximum Intensity (I say maximum because we know the in the middle -along the x-axis- there's always constructive interference) is the Sum of the Amplitudes from all three speakers squared: ##I_{total} = |A_1 + A_2 + A_3|^2 ##, but the three speakers have the same amplitude since they are connected to the same tone generator. Thus, $$ I_{total} = |3\sqrt{15}|^2 = 9*15=135mw/m^2 $$
 
I think i got the same result. I did this to get the total intensity

P0 = √(2vρI) = 3.65 PaI = P(0)/(2vρr^2) <==> r = P0/√(2vρI) = 1m

I = P/A <==>

3 speakers => P = 4π*(3*1)^2*15*10^-3 = 1.69 W

and the total intensity then becomes

I = 1.69 /(4π*1^2) = 0.135 w/m^2

On b)

How can i find the maximal intensity on the y-axis if a = λ/4 ?
 

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