Sound Intensity on a Field (no interference)

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SUMMARY

The discussion revolves around calculating sound intensity levels from two loudspeakers positioned at opposite ends of a field, with a measured intensity of 74.1 dB at the halfway point. The sound intensity at this point is determined to be 2.57e-5 W/m², with each speaker contributing half of this intensity, resulting in 1.28e-5 W/m² from each speaker. The user seeks to apply the equation Ia/Ib=rb²/ra² to find the sound intensity at a point one-quarter of the way from one speaker to the other. The approach is confirmed as correct by another participant.

PREREQUISITES
  • Understanding of sound intensity levels in decibels (dB)
  • Familiarity with the inverse square law in sound propagation
  • Knowledge of basic physics equations related to sound intensity
  • Ability to convert between decibels and watts per square meter (W/m²)
NEXT STEPS
  • Research the application of the inverse square law in sound intensity calculations
  • Learn about sound intensity level conversions from dB to W/m²
  • Explore the effects of distance on sound intensity in open environments
  • Study the principles of sound wave interference and its impact on intensity
USEFUL FOR

Students in physics, acoustics researchers, audio engineers, and anyone interested in understanding sound propagation and intensity calculations in open fields.

Ethan_Tab
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Homework Statement


Two loudspeakers on elevated platforms are at opposite ends of a field. Each broadcasts equally in all directions. At the halfway point, the intensity is 74.1dB.

What is the sound intensity level at a point one-quarter of the way from one speaker to the other along the line joining them?

Assume no interference and sound loss.

Homework Equations


Ia/Ib=rb2/ra2

The Attempt at a Solution


I've started by finding the sound intensity at the half way point in W/m^2

107.41=Ia/10-12
Therfore: Ia= 2.57e-5 w/m^2
Since this is the net sum of the two speakers each one only provides half of that therefore just before they combine, the Sound intensity at the half way point relative to each speaker is
1.28e-5 W/m^2

Do I just use this information to figure out Ib at 1/4th the distance with the equation I wrote down in Part 2?
 
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Ethan_Tab said:
I've started by finding the sound intensity at the half way point in W/m^2

107.41=Ia/10-12
Therfore: Ia= 2.57e-5 w/m^2
Since this is the net sum of the two speakers each one only provides half of that therefore just before they combine, the Sound intensity at the half way point relative to each speaker is
1.28e-5 W/m^2

OK

Do I just use this information to figure out Ib at 1/4th the distance with the equation I wrote down in Part 2?

Sounds good.
 
Cool, thanks for the help @TSny
 

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