- #1

fashion_fever

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## Homework Statement

evaluate:

higher limit of 36

lower limit of 0 (36+3x)^1/2 dx

## Homework Equations

i thought of using subsititution?

## The Attempt at a Solution

g(x)=36+3x

g'(x)=3

when x=0, u=36+3(0)=36

when x=36, u=36+3(36)=144

from lower limit of 36 to higher limit of 144

3(u)^1/2 du= 3(2/3)u^3/2 + C

substitute 36+3x back into u, i get: 2(36+3x)^3/2 + C

=[2(36+3(144))^3/2) + C ] - [ 2(36+3(36))^3/2] + C

= 2(468)^3/2 - 3456 + C

is this correct??

#### Attachments

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