How does sulfur form 6 bonds with fluorine?

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Sulfur hexafluoride (SF6) exhibits sulfur forming six bonds with fluorine, leading to a total of 12 valence electrons. This phenomenon is explained by sulfur's ability to undergo valence shell expansion, utilizing its empty 3d orbitals for bonding, despite d-electrons not participating in the bonding process. The hybridization in SF6 involves sp3d2 orbitals, which are linear combinations of one s, three p, and two d orbitals. Understanding these concepts clarifies the bonding behavior of sulfur in SF6.

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I was looking at sulfur hexafluoride and noticed that the sulfur forms 6 bonds with fluorine. Wouldn't 2 bonds put it at 8 valence electrons? How does it form so many extra bonds when it only needs 2?

Edit: I should word this as "How does sulfur form 6 bonds with fluorine? Wouldn't that give it 12 valence electrons?"

Thanks.
 
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Elements in period 3 and beyond can undergo a process known as valence shell expansion where the d-orbitals contribute to the valence shell.
 
No, the d-electrons play no role in the bonding of SF_6.
 
D-electrons do not play a role in the bonding of SF6, but sulfur's empty 3d orbitals do.
 
How does an atom have empty orbitals? Empty meaning no electrons in it? How can it have orbitals without electrons? Aren't the electrons themselves orbitals?

And wouldn't 6 bonds put the sulfur at 12 valence electrons? They want to be at 8, right?

Thanks for the replies.
 
leroyjenkens said:
How does an atom have empty orbitals? Empty meaning no electrons in it? How can it have orbitals without electrons? Aren't the electrons themselves orbitals?

And wouldn't 6 bonds put the sulfur at 12 valence electrons? They want to be at 8, right?

Thanks for the replies.

Electrons are not themselves orbitals. In layman's terms, orbitals can be described as the slots which may or may not be occupied by electrons at anyone time. An electron in an atom has a set of quantum states (n,l,ml,s). The values of n and l determine the kind of orbital (s,p,d,f,g...) the electron occupies, ml determines which orbital is occupied and s determines which of the two slots in the orbital is occupied by the electron.

Orbitals may combine to form hybrid orbitals, which are linear combinations of "normal" orbitals. For example, an sp3d2-orbital, which is the type present in SF6, is a linear combination of one s-, three p-, and two d-orbitals.
 
espen180 said:
Orbitals may combine to form hybrid orbitals, which are linear combinations of "normal" orbitals. For example, an sp3d2-orbital, which is the type present in SF6, is a linear combination of one s-, three p-, and two d-orbitals.

This has long been disprooved. d-orbitals do not participate in the bonding in molecules like SF_6.
I discussed this already in another thread https://www.physicsforums.com/showthread.php?t=405593&highlight=hybridization
(is there a more direct way to cite an older thread?)

For convenience here again the link to a more modern description
:http://dx.doi.org/10.1016/S1380-7323(99)80022-3
 
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