How Does Temperature Affect the Angular Velocity of a Rotating Aluminum Wheel?

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Homework Help Overview

The discussion revolves around the effects of temperature on the angular velocity of a rotating aluminum wheel, specifically focusing on a solid cylindrical wheel's response to thermal expansion as temperature increases from 20.0 to 95.0 degrees Celsius.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between thermal expansion and angular velocity, questioning the assumptions about constant velocity and the implications of frictionless bearings. They discuss conservation laws relevant to rotating objects, particularly angular momentum.

Discussion Status

The conversation has progressed through various interpretations of the problem, with participants offering insights into the conservation of angular momentum and how it relates to changes in radius due to thermal expansion. Guidance has been provided regarding the application of these concepts, though no consensus on the final outcome has been reached.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available and the assumptions that can be made about the system's behavior.

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Homework Statement


A 28.4-kg solid aluminum cylindrical wheel of radius 0.41m is rotating about its axle in frictionless bearings with angular velocity w = 32.8 rad/s. If the temperature is then raised from 20.0 degrees celsius to 95.0 degrees celcuis, what is the fractional change in angular velocity w?


Homework Equations


delta l = alpha*l*delta T T=temperature
v=rw w=angular frequency


The Attempt at a Solution


I used the thermal expansion equation and found the change in Radius r.
I also assumed that because the wheel was on frictionless bearings that velocity v was constant.
so finding the change in r, i pluged into the angular frequency equation delta w = v/delta r.

is that in any way correct?
 
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darkAzNk3n said:
I also assumed that because the wheel was on frictionless bearings that velocity v was constant.
This assumption is wrong, but other than that, you're kind of thinking along the right lines.

Think about it this way: the fact that the wheel is on frictionless bearings means that the force acting to rotate it is zero. That in turn means that the torque on the wheel is zero. What quantity is constant (a.k.a. conserved) for a rotating object with no torque on it?
 
diazona said:
. What quantity is constant (a.k.a. conserved) for a rotating object with no torque on it?

the only thing i can come up with is that the radius is constant but, wouldn't the wheel have to expand which would increase the radius for there to be a change in the angular velocity?
 
Nope, it's not the radius.

What conservation laws have you learned about?
 
diazona said:
Nope, it's not the radius.

What conservation laws have you learned about?

Conservation of energy and momentum pop up at the top of my head
 
OK, good, but there's a third conservation law that you'll need for this problem. What's the one that applies specifically to rotating objects?
 
diazona said:
OK, good, but there's a third conservation law that you'll need for this problem. What's the one that applies specifically to rotating objects?

Conservation of Angular Momentum?

dL/dt=0 and L = Iw = constant

I think.
 
Yep, that's the one. Now how can you use that in this problem?

As a first step, what's I for a solid cylindrical wheel?
 
I got I = 1/2 mr^2

then L = 1/2 mwr^2

but what bout the L?

do i find the change in radius with the thermal expansion equation then plug that radius back into the angular momentum equation?
 
  • #10
Why, do you have another idea as to how to proceed?

Try it and post your work here :wink:
 
  • #11
hmm

since we know L=Iw and since I=Mr^2/2, L = (wMr^2)/2=constant

and from thermal expansion equation, we know delta r = alpha*r0*delta T

we can then add r0 and delta r to find the new r

then we plug back into L = (wMr^2)/2
and from the conservation of angular momentum we know that L is a constant, we can find new w with the new r, w= 2L/Mr^2
and compare with initial w that's given

hard to follow sorry.
 
  • #12
Yep, that's exactly the way to do it.
 
  • #13
diazona said:
Yep, that's exactly the way to do it.

o Thanks for the help haha
one down.. four to go.
 
  • #14
for the fractional change of w, I got something small like 3.74 * 10^-3 rad/sec. is that right?
 
  • #15
Assuming you did the math correctly, I don't see why it shouldn't be.
 

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