MHB How does temperature affect the length of a steel measuring tape?

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Temperature significantly affects the length of a steel measuring tape due to its coefficient of linear expansion. At 70°F, a steel tape measures 100,000 feet, but at 10°F, it contracts. The calculation shows that the length of the tape at 10°F is approximately 99,651.24 feet. Consequently, a distance of 90,000 feet at 10°F corresponds to a reading of about 110,723.6 feet. This demonstrates the importance of accounting for temperature when using steel measuring tapes.
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A certain steel tape is known to be 100000 feet long when the temperature of 70°F . When the tape is at a temperature of 10°F, what reading corresponds to a distance of 90000 ft? Coefficient of linear expansion of the tape is 5.833 x 10-6 per °F.
 
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My first thought was "what in the world is a "reading"? Finally I realized- this is NOT just a "steel tape" but a steel measuring tape! Let "x" be the length of the tape at 10 degrees F. When the temperature increases from 10 degrees F to 70 degrees F, an increase of 60 degrees F, the tape will have increased by a factor of 1+ 5.833 x 10^(-6) x 60= 1+ 349.98 X 10^(-6)= 1+ 3.4998 x 10^(-4)= 1.00034998. Since the length after the expansion is 100,000 feet, we must have 1.00034998x= 100,000. So the length of the tape at 10 degrees F is x= 100000/1.0034998= 99651.24058. The reading, at 90,000 feet, at 10 degrees F is given by \frac{y}{90000}= \frac{100000}{99651.24058}. y= 10(99651.24058)/9= 110723.6 feet.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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