How Does Tension in a Frictionless Pulley System Behave with Balanced Forces?

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The discussion focuses on the behavior of tension in a frictionless pulley system with balanced forces, specifically involving a 2.0 kg mass on a horizontal surface and a 1.5 kg mass suspended. The tension in both strings is equal to the weight of the suspended mass, which is 14.7 N (1.5 kg * 9.8 m/s²). The system remains in equilibrium due to the absence of acceleration, confirming that the tension forces in both strings are equal and consistent with the weight of the hanging mass.

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1. A 2.0 kg mass sits on a frictionless horizontal surface. The mass is attached by a weightless string running over a frictionless pulley attached to a 1.5 kg mass. An additional string exerts a force on the block on the mass on the surface so that no motion results. Find the tension in each of the strings.



2.



3. I just wonder if this problem is as easy as it seems. Fg on mass 2 is equal to the tension force on mass 2 therefore the tension in string 2 is equal to the weight of the object. If that is the case and there is no acceleration to either mass in the problem the tension force for both strings is equal to the weight of the suspended mass.
 
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Sounds right as long as the additional string is pulling horizontally.
 
yea diagram looks like

---------block---------
|
|
|
block
 
Good. Then I think your reasoning is correct! :smile:
 

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