How Does Tension in the String Compare to the Force on Block A?

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In a system with two blocks, A and B, connected by a massless string on a frictionless surface, the tension in the string is analyzed in relation to the force applied to block A. The force exerted by the hand on block A must be greater than the tension in the string because block A experiences a net force that results in acceleration. Since both blocks accelerate together, the tension in the string remains constant throughout. The conclusion is that the force of the hand on block A exceeds the tension in the string acting on block B. This understanding clarifies the relationship between the forces in the system.
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Homework Statement


The hand in the figure is pushing on the back of block A. Blocks A and B, with mass B > mass A, are connected by a massless string and slide on a frictionless surface.

Is the force of the string on B larger than, smaller than, or equal to the force of the hand on A?

Picture: http://img713.imageshack.us/img713/1030/physicsq.jpg

Homework Equations


The Attempt at a Solution



From my free body diagram, block B has a tension towards the right that should be less than the force applied to block A as they both move with the same acceleration.
 
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Consider the forces on block A.
 
Block A has a force to the right and tension in the opposing direction. Because of conservation of string, the tension should be the same for Block B? Since this is on a frictionless surface, nothing is opposing the force applied on A so there will be an acceleration to the right meaning tension should be less than the force?
 
I'd state it this way: The only forces on block A are the applied force and the string tension. The the blocks accelerate, so there must be a net force on A, thus the applied force must be greater than the tension. (And the tension is the same throughout a massless rope.)
 
Thank you! This thread can be closed.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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