How Does the Conservation of Energy Explain the Motion of Objects Over a Pulley?

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SUMMARY

The discussion focuses on applying the principle of conservation of energy to analyze the motion of two objects connected by a light string over a frictionless pulley. Specifically, it addresses the calculation of the speed of a 3.00-kg object when a 5.00-kg object hits the ground and the maximum height the 3.00-kg object reaches. The correct approach involves using the equation 1/2*m*v² = m*g*h, where g is the acceleration due to gravity (9.8 m/s²), to solve for height.

PREREQUISITES
  • Understanding of the conservation of energy principle
  • Familiarity with basic physics equations involving mass, velocity, and height
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to analyze motion in a pulley system
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn about the dynamics of pulley systems in physics
  • Explore kinematic equations related to motion and energy
  • Investigate the effects of friction in pulley systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation principles, as well as educators seeking to clarify concepts related to pulleys and motion.

Leesh09
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Homework Statement


Two objects are connected by a light string passing over a light frictionless pulley as shown
in the figure. The object of mass 5.00-kg is released from rest. Using the principle of
conservation of energy, (a) determine the speed of the 3.00-kg object just as the 5.00-kg
object hits the ground. (b) Find the maximum height to which the 3.00-kg object rises.



Homework Equations





The Attempt at a Solution


I believe I am all set with part a. My question is on part B. Is it correct to say 1/2*m*v2 = m*g*h and then use 9.8 as v also and solve for h?
 
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The statement of the problem is not very informative without a figure. Can you post one or at least describe what the figure shows?
 

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