How Does the Constant Gradient Condition Affect Solutions to the Wave Equation?

  • Thread starter Thread starter chaotixmonjuish
  • Start date Start date
  • Tags Tags
    Wave Wave equation
Click For Summary
SUMMARY

The discussion focuses on solving the wave equation \( u_{tt} - u_{xx} = 0 \) under specific conditions, particularly with the gradient \( u_x(x,t) \) being constant along the line \( x = 1 + t \). The initial condition is set as \( u(x,0) = 1 \) for all \( x \in \mathbb{R} \), and the value \( u(1,1) = 3 \) is provided. The derived solutions are \( u(x,t) = t + \frac{1}{2}(4t + 2t^2) \) for \( x > 0 \) and \( u(x,t) = t + \frac{1}{2}(\frac{3}{2} + 5t + \frac{3t^2}{2}) \) for \( 0 < x < t \).

PREREQUISITES
  • Understanding of wave equations and their properties
  • Familiarity with Neumann boundary conditions
  • Knowledge of partial differential equations (PDEs)
  • Basic calculus and differential equations
NEXT STEPS
  • Study the derivation of solutions for wave equations with Neumann boundary conditions
  • Explore the implications of constant gradients in PDEs
  • Learn about the method of characteristics for solving wave equations
  • Investigate initial value problems in the context of wave equations
USEFUL FOR

Mathematicians, physicists, and engineering students focusing on wave phenomena, as well as researchers dealing with partial differential equations and boundary value problems.

chaotixmonjuish
Messages
284
Reaction score
0
Let u be a solution of the wave equation utt-uxx=0 on the whole plane. Suppose that ux(x,t) is a constant on the line x=1+t. Assume that u(x,0)=1 for all x in R and u(1,1,)=3. Find such a solution u.

I need help trying to incorporate the ux(x,t) is a constant on the line x=1+t
 
Physics news on Phys.org
So I got this as a solution by plugging it into an equation for wave equations with a Neumann condition:

u(x,t)= t+1/2(4t+2t^2) x>0

u(x,t)= t+1/2(3/2+5t+3t^2/2) 0<x<t
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
3K