How Does the General Leibniz Formula Apply to Integrals with Variable Limits?

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Discussion Overview

The discussion revolves around the application of the general Leibniz formula to integrals with variable limits, focusing on its mathematical implications and the use of the chain rule in this context.

Discussion Character

  • Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant requests clarification on the application of the general Leibniz formula.
  • Another participant suggests using the chain rule and denotes the upper limit of the integral as y(x), proposing that this leads to the expression dF/dx = dF/dy dy/dx.
  • A participant acknowledges the suggestion and expresses intent to review the information provided.
  • Another participant presents the general Leibniz formula in mathematical notation, detailing the derivative of an integral with variable limits.

Areas of Agreement / Disagreement

The discussion does not appear to reach a consensus, as participants are exploring different aspects of the formula and its application without resolving any disagreements.

Contextual Notes

There may be limitations related to the assumptions required for applying the general Leibniz formula, as well as the dependence on the definitions of the functions involved.

kid_abraxis
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can anyone shed some light on this little monster?
 

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What you should do is to use the chain rule. Denote the upper limit of the integral (the limit which itself is an integral) as y(x). Then you should be able to see that dF/dx = dF/dy dy/dx.
 
i'll take a look. ta
 
The general Leibniz' formula is
[tex]\frac{d}{dx}\int_{\alpha(x)}^{\beta(x)} F(x,t)dt= \frac{d\beta(x)}{dx}F(x,\beta(x))- \frac{d\alpha(x)}{dx}F(x,\alpha(x))+ \int_{\alpha(x)}^{\beta(x)}\frac{\partial F(x,t)}{\partial x} dt[/tex]
 

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