How does the gradient of the graph compare to the W force

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The discussion focuses on understanding the relationship between the gradient of a mass versus 1/acceleration graph and weight force. The gradient, calculated as 11/20, is compared to the weight force derived from W = mg, where the mass is 0.001 kg and gravity is 9.8 m/s², resulting in W = 0.0098 N. Participants clarify that in this context, the formula F = ma should be rearranged to fit the graph's format, with mass as the dependent variable and 1/acceleration as the independent variable. There is confusion regarding which force is represented by F in the experiment, emphasizing the need for clear definitions. Understanding the slope's representation in terms of the graph's coordinates is crucial for accurate analysis.
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Homework Statement


How does the gradient of the graph compare to the weight force?
The graph is a Mass vs 1/Acceleration graph (y axis = mass, x-axis = Acceleration, It was mentioned to do this.)

Homework Equations


Explain by referring to the formula for Newton's Second Law.

The Attempt at a Solution



I know that F = m * a
Could someone explain what must be done and what the use of a reciprocal is?

Thanks!
 
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Hi,
The slope of the graph from the line of best fit is 11/20.
The problem I am having is with the comparison of the slope to the weight force which I calculated to be
W = m * g mass of 1 gram = 0.001 KG

W = 0.001 * 9.8

W = 0.0098 N
upload_2017-6-19_22-19-58.png
 
You quote F=ma. I'm not sure which force F represents in your experiment, but I assume it is not the weight of the mass, although you mention W=mg in the later post.

You are used to graphs like y=slope * x. Here, you have y standing for m and x standing for 1/a. So rearrange your F=ma into the form y = slope * x.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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