ChrisVer
Science Advisor
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How does having a non-zero vev gives particles mass.
The main thing is to understand that the mass of the fields appear in the Lagrangian density as (field)2 terms (field self-interactions). One possible explanation that can help you understand it, is that the fields will have to contain some certain amount of energy just to exist (to have the mass) and that's 1 reason why the quadratic terms of fields are the mass terms (Lagrangian and Hamiltonian are both connected to the energy of your system). Another way is that they will give the correct equations of motion for the fields.
Then you can go to the Lagrangian and see what is happening if you allow for a Higgs field. There is a Yukawa term allowed in your lagrangian which will couple two fermionic fields to a scalar one. Since the Higgs field H is a scalar it's able to be coupled to your fermions F in the form:
\bar{F}HF . If now the Higgs field H has a vev different to zero, then it means that this interaction term will give some energy even if you are looking at the vacuum value. Let's say that this vev is a you will get:
\bar{F}HF=a \bar{F}F
where then you can say that a is the (bare) mass.
The Higgs boson will appear by perturbing around the vacuum, that is doing something like: H(x)= a + h(x) then you will also have a term like: a \bar{F}F+ \bar{F} h(x) F which will correspond to your fermions having a mass a coming only because of the Higgs field's vev, and also interact with the Higgs boson (not so strongly interesting).
The main thing is to understand that the mass of the fields appear in the Lagrangian density as (field)2 terms (field self-interactions). One possible explanation that can help you understand it, is that the fields will have to contain some certain amount of energy just to exist (to have the mass) and that's 1 reason why the quadratic terms of fields are the mass terms (Lagrangian and Hamiltonian are both connected to the energy of your system). Another way is that they will give the correct equations of motion for the fields.
Then you can go to the Lagrangian and see what is happening if you allow for a Higgs field. There is a Yukawa term allowed in your lagrangian which will couple two fermionic fields to a scalar one. Since the Higgs field H is a scalar it's able to be coupled to your fermions F in the form:
\bar{F}HF . If now the Higgs field H has a vev different to zero, then it means that this interaction term will give some energy even if you are looking at the vacuum value. Let's say that this vev is a you will get:
\bar{F}HF=a \bar{F}F
where then you can say that a is the (bare) mass.
The Higgs boson will appear by perturbing around the vacuum, that is doing something like: H(x)= a + h(x) then you will also have a term like: a \bar{F}F+ \bar{F} h(x) F which will correspond to your fermions having a mass a coming only because of the Higgs field's vev, and also interact with the Higgs boson (not so strongly interesting).