How Does the Hubble Parameter Relate to Galaxy Movement?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Komorebi
Messages
1
Reaction score
0
This is the time derivative to calculate the speed which a galaxy moves away from another galaxy. I don't understand how they get from da/dt (xi − x1) to (∙a)/a a(t). (xi − x1). Could anyone explain this? vi(t) = d/dt (ri(t) − r1(t))
= d/dt a(t)(xi − x1)
= da/dt (xi − x1)
= (∙a)/a a(t). (xi − x1) !
=(∙a)/a (ri(t) − r1(t))
= H(t) (ri(t) − r1(t))

[ ∙a= da/dt ]
 
Last edited:
Astronomy news on Phys.org
Komorebi said:
how they get from da/dt (xi − x1) to (∙a)/a a(t). (xi − x1)
Since ##\frac{da}{dt}=\dot a##
and ##\frac{a}{a}=1##
You have ##\frac{da}{dt} \Delta x## multiplied by 1 to net you ##\frac{\dot a}{a}a\Delta x##.

If it still doesn't click, Leonard Susskind derives this here in a slightly different, but essentially the same manner:

(starting at 21:22 mark)
 
  • Like
Likes   Reactions: Komorebi