How Does the Hubble Parameter Relate to Galaxy Movement?

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SUMMARY

The discussion focuses on the derivation of the Hubble parameter in relation to galaxy movement, specifically the transition from the equation da/dt (xi − x1) to (∙a)/a a(t) (xi − x1). The equation vi(t) = d/dt (ri(t) − r1(t)) is established, leading to the conclusion that the Hubble parameter H(t) can be expressed as H(t) = (∙a)/a (ri(t) − r1(t)). The importance of defining variables in equations is emphasized, as conventions may vary among different users.

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  • Understanding of the Hubble parameter and its significance in cosmology
  • Familiarity with calculus, particularly derivatives
  • Knowledge of basic astrophysical concepts, such as galaxy movement and redshift
  • Ability to interpret mathematical equations and symbols used in physics
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  • Study the derivation of the Hubble parameter in detail using Leonard Susskind's lectures
  • Explore the implications of the Hubble parameter on cosmic expansion
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Komorebi
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This is the time derivative to calculate the speed which a galaxy moves away from another galaxy. I don't understand how they get from da/dt (xi − x1) to (∙a)/a a(t). (xi − x1). Could anyone explain this? vi(t) = d/dt (ri(t) − r1(t))
= d/dt a(t)(xi − x1)
= da/dt (xi − x1)
= (∙a)/a a(t). (xi − x1) !
=(∙a)/a (ri(t) − r1(t))
= H(t) (ri(t) − r1(t))

[ ∙a= da/dt ]
 
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It's a good idea to define the variables in an equation. Not everyone uses the same 'conventions'.
 
Komorebi said:
how they get from da/dt (xi − x1) to (∙a)/a a(t). (xi − x1)
Since ##\frac{da}{dt}=\dot a##
and ##\frac{a}{a}=1##
You have ##\frac{da}{dt} \Delta x## multiplied by 1 to net you ##\frac{\dot a}{a}a\Delta x##.

If it still doesn't click, Leonard Susskind derives this here in a slightly different, but essentially the same manner:

(starting at 21:22 mark)
 
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