- #1

olgerm

Gold Member

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2 bodies that have distance d between them are distancing from each other because Hubbles law. at time t=0 distance between them was d(0) and speed between them was 0.

If no force interacts with them then distance is increasing by rate ##\frac{\partial d}{\partial t}=H_0*d##

Is it correct?

Their potential energy is increasing by rate ##\frac{\partial E_{pot}}{\partial t}=\frac{(m_1*m_2*k_G-q_1*q_2*k_E)*H_0*e^{-t*H_0}}{d(0)}##Is that correct?

Where is that energy coming from? How is total energy conserved?

If a force interacts between the 2 bodies, that keeps distance same (##\frac{\partial d}{\partial t}=0##)

Is the energy in that scenario converting to some other form of energy?

I know that Hubbles law is very small in that scale, but if the 2 bodies are proton and electron in hydrogen atom, would hobbles law make this atom unstable?

##H_0## is Hubble parameter.

##k_G## is gravitational constant.

##k_E## is Coulomb's constant

If no force interacts with them then distance is increasing by rate ##\frac{\partial d}{\partial t}=H_0*d##

Is it correct?

Their potential energy is increasing by rate ##\frac{\partial E_{pot}}{\partial t}=\frac{(m_1*m_2*k_G-q_1*q_2*k_E)*H_0*e^{-t*H_0}}{d(0)}##Is that correct?

Where is that energy coming from? How is total energy conserved?

If a force interacts between the 2 bodies, that keeps distance same (##\frac{\partial d}{\partial t}=0##)

Is the energy in that scenario converting to some other form of energy?

I know that Hubbles law is very small in that scale, but if the 2 bodies are proton and electron in hydrogen atom, would hobbles law make this atom unstable?

##H_0## is Hubble parameter.

##k_G## is gravitational constant.

##k_E## is Coulomb's constant

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