How Does the Integral of 1/(4y-1) with Respect to x Evaluate from 0 to 1?

[pureouchies4717]

integral of 1/(4y-1) dx from 0 to 1

im stumped

 

[d_leet]

integral of 1/(4y-1) dx from 0 to 1

im stumped

Whats the integral of 1/y ?

Ohh I missed what LocationX pointed out, are you sure it's a function of y that you are integrating with respect to x? Or is the y supposed to be x, or the dx dy?

 

[LocationX]

if it is with respects to x, then the integral is just $$\frac{x}{4y-1}$$