pureouchies4717
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integral of 1/(4y-1) dx from 0 to 1
im stumped
im stumped
The integral of 1/(4y-1) with respect to x from 0 to 1 evaluates to x/(4y-1) after recognizing that y is treated as a constant during integration. The discussion highlights confusion regarding the variable of integration, clarifying that the integral is indeed with respect to x, not y. This distinction is crucial for correctly applying integration techniques in calculus.
PREREQUISITESStudents studying calculus, educators teaching integration techniques, and anyone looking to clarify their understanding of variable treatment in integrals.
nick727kcin said:integral of 1/(4y-1) dx from 0 to 1
im stumped