How Does the Kernel Equaling the Image Explain A Squared Equaling Zero?

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Homework Help Overview

The discussion revolves around understanding the concepts of the kernel and image of a matrix, specifically for the matrix A = (2,1)(-4,-2). Participants are tasked with finding the kernel and image, calculating A squared, and explaining the result in the context of linear transformations.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definitions and properties of the kernel and image, with some attempting to clarify the relationship between them. There are questions about how to interpret the result of A squared equaling the zero matrix and how this relates to the kernel and image.

Discussion Status

Some participants have provided insights into the nature of the kernel and image, suggesting that the image of A coincides with its kernel. There is ongoing exploration of the implications of A squared resulting in the zero matrix, with various interpretations being considered.

Contextual Notes

Participants note that the kernel is not limited to a single vector and that there are infinite vectors within it. There is also mention of geometric interpretations related to the mapping of vectors by the matrix A.

tomeatworld
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Homework Statement


i) Find the Image and Kernel of A = (2,1)(-4,-2) (where each bracket is a row).
ii) Calculate A2 and use i) to explain your result.


Homework Equations


None

The Attempt at a Solution


So I can do everything up to the very last bit (i think anyway).
i) The Kernel = (1,-2) = Image.
ii) A2 = 0 but this is where I don't know what to say. How do I use part i) to explain the 0 matrix found?
 
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tomeatworld said:

Homework Statement


i) Find the Image and Kernel of A = (2,1)(-4,-2) (where each bracket is a row).
ii) Calculate A2 and use i) to explain your result.


Homework Equations


None

The Attempt at a Solution


So I can do everything up to the very last bit (i think anyway).
i) The Kernel = (1,-2) = Image.
ii) A2 = 0 but this is where I don't know what to say. How do I use part i) to explain the 0 matrix found?
For i, you have the basic idea, but it needs some refinement. The kernel is not just one vector; there are an infinite number of vectors in the kernel of A. Likewise, the range is not just one vector either.

Geometrically, A maps any vector along the line 2x + y = 0 to the zero vector. A maps any vector x not along the the line 2x + y = 0 to a vector along this line. IOW, if x is not in the kernel of A, A projects it onto this line.

For ii, since A2x = A(Ax)think about what A does to a vector x, and then think about what A does to a vector Ax.
 
OK i think i understand what you mean about the kernel. so applying to to another question, if I have the matrix:

A=[{1,0,-2},{2,2,0},{0,3,6}] and I wanted to find the kernel, I'd reduce it down to:

A=[{1,0,-2},{0,1,2},{0,0,0}] and thus the kernel is:

Ker[A] = f[1,-1,2] where f is any number.

Is that about right?
 
I think you got the 1's and 2's switched, i.e.

[tex]\textrm{Ker}[A] = \{\vec{x}\in \Re^3\,|\, \vec{x} = f(2,-2,1), f \in \Re\}[/tex]
 
tomeatworld said:

Homework Statement


i) Find the Image and Kernel of A = (2,1)(-4,-2) (where each bracket is a row).
ii) Calculate A2 and use i) to explain your result.


Homework Equations


None

The Attempt at a Solution


So I can do everything up to the very last bit (i think anyway).
i) The Kernel = (1,-2) = Image.
ii) A2 = 0 but this is where I don't know what to say. How do I use part i) to explain the 0 matrix found?
The point here is that the image is the kernel! For any vector v, Av is in the kernel of A so A(Av)= 0.
 

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