How does the kinetic energy change for a varying mass?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 3K views
Reshma
Messages
749
Reaction score
6
Show that for a single particle with constant mass the equation of motion implies the following differential equation for the kinetic energy:
[tex]{dT\over dt} = \vec F \cdot \vec v[/tex]

while if the mass varies with time the corresponding equation is
[tex]{d(mT)\over dt} = \vec F \cdot \vec p[/tex]

Proof:

I was able to prove the first part:
[tex]T = {1\over 2}mv^2[/tex]
[tex]{dT\over dt} = {1\over 2} {d(mv^2)\over dt} = \vec v \cdot m{d\vec v \over dt} = \vec F \cdot \vec v[/tex]

But I am unable to prove the second part. Please help.
 
Physics news on Phys.org
what does mT equal in terms of m and v? in terms of p?
mv=p
F=dp/dt

try to play with the equation a little and substitute p in.