How Does the Limit Equal sqrt(e)?

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The limit of the expression [1+1/(2x)]^x as x approaches negative infinity is shown to equal sqrt(e). By letting y equal the expression and taking the natural logarithm, the limit of ln(y) simplifies to x ln[1+1/(2x)]. Applying L'Hôpital's rule leads to the conclusion that the limit of ln(y) is 1/2. Consequently, this implies that the limit of y is e^(1/2), confirming that the limit equals sqrt(e). The discussion highlights the importance of recognizing the relationship between the limit of ln(y) and the original limit.
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Homework Statement



Show that:

Lim [1+1/(2x)]^x = sqrt(e)
x->-inf

2. Homework Equations /theorums

l'hospital's rule

The Attempt at a Solution



Let y= [1+1/(2x)]^x

lny=ln [1+1/(2x)]^x

lny= x ln [1+1/(2x)]

Then
Ln Lim (y)=
x->-inf

Lim (lny)=
x->-inf

Lim x ln [1+1/(2x)]=
x->-inf

By l'hopital

and evaluating the resulting limit as x->-inf

I get 1/2.How does this limit equal the sqrt of "e"?
I know that it does, as i found a limit calculator online and sqrt(e) was the answer... but no matter how I try to do it, I can't get to sqrt"e".
 
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You found lim ln(y) is 1/2. What does that make lim y?
 
Last edited:
Oh...e^(1/2). Thank you very much! Although i feel a little dumb, the darn thing was staring me in the face. By the way thanks for the quick reply as well.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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