How does the moment of inertia scale?

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SUMMARY

The moment of inertia scales with the square of the scaling factor when all design dimensions are multiplied by a factor f. Specifically, if the mass increases by f^3 due to volume scaling, the moment of inertia I is multiplied by f^5, as indicated by the equation I = k * m * r^2, where k is a shape-dependent constant. For a 1/48 scale model with a rotational kinetic energy of 2.5J, the full-scale object's kinetic energy at the same angular velocity will be 2.5J * (48^5), demonstrating the significant impact of scaling on kinetic energy.

PREREQUISITES
  • Understanding of moment of inertia equations for various shapes (point mass, solid sphere, hollow sphere, rod).
  • Familiarity with the concepts of scaling factors in physics.
  • Basic knowledge of rotational kinetic energy and its calculation.
  • Ability to manipulate algebraic equations involving constants and variables.
NEXT STEPS
  • Research the derivation of moment of inertia for different geometric shapes.
  • Learn about the relationship between mass, volume, and scaling in physics.
  • Explore the implications of scaling on kinetic energy in rotational systems.
  • Study the effects of changing dimensions on physical properties in engineering design.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators seeking to explain the concept of moment of inertia and its scaling effects.

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Homework Statement



If we multiply all of the design dimensions by a scaling factor f, it's volume and mass will be multiplied by f^3. (a) By what factor will its moment of inertia be multiplied? (b) And if a 1/48 scale model has a rotational kinetic energy of 2.5J, what will be the kinetic energy for the full-scale object of the same material rotating at the same angular velocity?

Homework Equations



The Attempt at a Solution



I have absolutely no idea what they are talking about. I feel like I missed an entire chapter, but I am sure that I didn't. All the other questions in my book leading up to this one have been the usual ones that ask me to find a value when dealing with the moment of inertia. What is this asking.
 
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Scale Factors

If you look at some of the moment of inertia equations you know, you'll see how we can address this question.

For a point mass, it's I = \frac{2 m r^2}{5}. For a solid sphere, I = \frac{2 m r^2}{5}. For a hollow sphere, I = \frac{2 m r^2}{3}. Rod about the end I = \frac{1 m r^2}{3}. Rod about the middle: I = \frac{1 m r^2}{12}.

The only thing that is changing is the constant in front.

The moment of inertia is given by the equation I=k*m*r^2, where k is the constant that depends on the shape. So the moment increasesas the mass increases, and increases like the square of the radius.

To find the scaling, you just multiply each quantity by a scale factor, f. We have to multiply by f3 for mass (since mass increases with increasing *volume*). We multiply each term of r by f.

Hope that helps.

Dr Peter Vaughan
BASIS Peoria Physics
 
sonnyfab said:
If you look at some of the moment of inertia equations you know, you'll see how we can address this question.

For a point mass, it's I = \frac{2 m r^2}{5}. For a solid sphere, I = \frac{2 m r^2}{5}. For a hollow sphere, I = \frac{2 m r^2}{3}. Rod about the end I = \frac{1 m r^2}{3}. Rod about the middle: I = \frac{1 m r^2}{12}.

The only thing that is changing is the constant in front.

The moment of inertia is given by the equation I=k*m*r^2, where k is the constant that depends on the shape. So the moment increasesas the mass increases, and increases like the square of the radius.

To find the scaling, you just multiply each quantity by a scale factor, f. We have to multiply by f3 for mass (since mass increases with increasing *volume*). We multiply each term of r by f.

Hope that helps.

Dr Peter Vaughan
BASIS Peoria Physics

Oh, thank-you so much!
 

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