How Does the Moon's Position Affect Its Gravitational Pull on You?

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Homework Help Overview

The discussion revolves around the gravitational effects of the Moon on an individual based on its position relative to Earth. The problem involves calculating the change in gravitational pull and weight as the Moon moves from being directly overhead to being on the opposite side of Earth.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the gravitational force calculations between the individual and the Moon, questioning the distances involved and whether to use their own mass in the calculations.

Discussion Status

Participants are actively engaging with the problem, attempting calculations and clarifying the distances involved. Some have offered guidance on the use of proportions and the significance of the distances, while others express confusion about the setup and specific values needed for the calculations.

Contextual Notes

There is some uncertainty regarding the distances used in the gravitational force calculations, with participants questioning the correct values for the Moon's position in relation to the individual. The problem does not explicitly require finding Earth's gravitational pull on the individual, which has led to some confusion.

G-reg
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Homework Statement


Some people believe that the Moon controls their activities. The Moon moves from being directly on the opposite side of Earth from you to be being directly overhead. Assume that the Earth-Moon (center-to-center) distance is 3.82 multiplied by 108 m and Earth's radius is 6.37 multiplied by 106.

(a) By what percent does the Moon's gravitational pull on you increase?


(b) By what percent does your weight (as measured on a scale) decrease?


Homework Equations


F = (GMm)/r^2




The Attempt at a Solution



First I found the force of the gravitational force between me and the moon, then for me and the Earth. Then I set up a proportion and found the percent that the gravitational force between me and the moon is to the gravitational force between me and the Earth.

F(moon) = (6.67e-11 * 7.36e22 * 70.76)/(9.55e7)^2 = 3.81e-2

F(Earth) = (6.67e-11 * 5.98e24 * 70.76)/(9.55e7)^2 = 8.56

F(moon)/F(Earth) = x/100

x = [100 * F(moon)] / F(Earth) = .44
 
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the problem does not actually ask u to find Earth's gravitational pull on you :D

it does not hurt though ;)
 
So the answer to the first one is just the gravitational force between me and the moon?
I'm still confused lol.
 
the distance between u and the moon is different for both cases :)
 
Ok you that makes sense. So the "r" in the equation would be different for each case. But do you think that I'm supposed to use my own mass for the problem?
 
try it first with what we have so far :)
 
Ok here we go..

F(moon_opposite side) = (6.67e-11 * 7.36E22 * 70.76) / (3.82e8)^2 = 2.4e-3

F(moon_overhead) = (6.67e-11 * 7.36E22 * 70.76) / (6.37e6)^2 = 8.56

now proportion?
 
u got the distances wrong :)
 
oh lol so..let's see..

is the distance for the "moon_opposite side" = 3.88e8?
and the other distance is 3.82e8?
 
  • #10
done, give me cookies :D
 
  • #11
the other distance is 3.76 e8
 
  • #12
haha how'd you get 3.76e8?
 
  • #13
try drawing the diagram, u'll see :)
 
  • #14
G-reg said:
oh lol so..let's see..

is the distance for the "moon_opposite side" = 3.88e8?
Yes.
...and the other distance is 3.82e8?
No, that's the distance from the moon to the center of the Earth. You would use that distance if you were located at the center of the Earth, which you aren't in this problem.
 

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