How does the proof connect the principles to show the elementary inequality?

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    Elementary Inequality
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The discussion focuses on the proof connecting the principles of absolute values to demonstrate the elementary inequality \(\mid a - b \mid < 1 \to \mid a \mid < \mid b \mid + 1\). The key steps involve using the triangle inequality, specifically \(|a - b| \le |a| + |b|\), and manipulating the expressions to show that \(|a| - |b| \le |a - b|\). This leads to the conclusion that the desired inequality holds true based on these established principles.

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duke_nemmerle
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I'm looking over a proof and I'm wondering from which principles does it follow that
[tex]\mid a - b \mid < 1 \to \mid a \mid < \mid b \mid + 1[/tex]

I can see that [tex]|a - b | \le |a| + |-b| = |a| + |b|[/tex] and that [tex]|a| - |b| < |a| + |b|[/tex] but I just can't connect the dots.
 
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duke_nemmerle said:
I'm looking over a proof and I'm wondering from which principles does it follow that
[tex]\mid a - b \mid < 1 \to \mid a \mid < \mid b \mid + 1[/tex]

I can see that [tex]|a - b | \le |a| + |-b| = |a| + |b|[/tex] and that [tex]|a| - |b| < |a| + |b|[/tex] but I just can't connect the dots.


Ahh, got it [tex]|a| = |(a+b)-b| \le |a-b| + |b|[/tex] which means [tex]|a| - |b| \le |a-b|[/tex] the result immediately follows
 

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