How Does the Radius Affect the Magnetic Field Inside a Solenoid?

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SUMMARY

The magnetic field (B) inside an infinitely long solenoid is uniform and does not depend on the radius (R) of the solenoid. According to Ampère's law, the differential length (dl) is equal to L when integrated along the solenoid's length. The enclosed current (Ienc) is calculated as the product of the current (I) and the number of turns per unit length (N), leading to the conclusion that B = μ₀NI, where μ₀ is the permeability of free space. The radius does not factor into the calculation of the magnetic field inside the solenoid.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with magnetic fields and solenoids
  • Knowledge of the permeability of free space (μ₀)
  • Basic calculus for integration
NEXT STEPS
  • Study the derivation of the magnetic field inside a solenoid using Ampère's Law
  • Explore the concept of magnetic field lines and their uniformity in solenoids
  • Learn about the applications of solenoids in electromagnetic devices
  • Investigate the effects of varying current and number of turns on the magnetic field strength
USEFUL FOR

Physics students, electrical engineers, and anyone studying electromagnetism or designing electromagnetic devices will benefit from this discussion.

Chip90
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Homework Statement



There is an infinetly long solenoid with current I, radius R, and N loops/unit length. Find the B field in the axis of the solenoid.

Homework Equations



792d084dfe4651c02d935c1490df17cd.png



The Attempt at a Solution



So that eq. can be narrowed to

B integral dl = Uo I

the only problem is I can't find dl its not 2*pi*R, 2r, 2RN... I am not sure what's wrong here.

I've made a similar diagram where the two edges and the side on the outside have a B field of 0.

solxsect.gif


Any ideas?
 
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any ideas? I also got
'
sol2.gif


but now sure how they got that from amperes law? ir is that the answer? thanks.
 

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That's correct. The differential length is simply L when integrated, since the magnetic field runs parallel to the axis of the solenoid. The enclosed current Ienc is the current I running through each turn multiplied by the number of turns in the solenoid, or N*I.

Hopefully that helps.
 
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?
 
Last edited:
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

You draw the gaussian loop enclosing only half of the inside of the solenoid and the other half s outside. There is no "r" because dl = L when integrated over the length of the solenoid.

Because B does not depend on the radius of the solenoid, the B field inside the solenoid is uniform, much like the E-field between a parallel plate capacitor is uniform.
 
ahha that makes sense.. thanks!
 
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

The vertical components don't matter since it's a dot product. The length outside of the solenoid is infinitely far away. At a point infinitely far away the magnetic field is 0, therefore it doesn't matter. That leaves the only important part as the horizontal line inside the solenoid. Therefore it's simply L (or X in this case.)
 

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