How Does the Rotation Period Change When a Star Expands to Six Times Its Volume?

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Homework Help Overview

The discussion revolves around the effects of a spherical star expanding to six times its volume while maintaining constant mass. Participants explore how this expansion influences the star's rotation period, particularly focusing on the relationship between rotational inertia and angular momentum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of angular momentum and how rotational inertia changes with the star's expansion. Questions arise about the mathematical relationships involved, particularly regarding the radius and its effect on inertia.

Discussion Status

Some participants have provided hints and guidance on the conservation principles at play, while others are verifying their understanding of the formulas related to moment of inertia and angular velocity. There is a mix of correct reasoning and some confusion regarding the specific formulas to use.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for deriving solutions. There is an emphasis on understanding the relationships between variables rather than arriving at a final answer.

dnt
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ok the question is a spherical star expands to 6 times its volume but its mass remains constant and is uniformly distributed - how does the period of rotation change?

obviously it rotates slower and thus the period goes up, but i don't know how to solve it mathematically. can someone give me some pointers and get me going in the right direction? is there a main equation i should be using and do i need to find the ratio of the radii before and after the star expands?

thanks.
 
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Hint: What's conserved? How does the rotational inertia change when the star expands? (Yes, you'll need to know how the radius changes.)
 
angular momentum is conserved.

and rotational inertia increases as the star expands, hence the angular velocity will go down to conserve angular momentum (L=Iw), right?

and if the volume goes up by 6 times, it means the radius went up by ~1.8 times.

do i then square that value because I=mr^2?

which means the inertia went up by (1.8)^2 = 3.3 and therefore the angular velocity (w) went down by 3.3 to compensate for that? am i understanding this correctly?
 
Sounds like you have the right idea!

[tex]I = 2/5 m r^2[/tex]

[tex]r_2 = 6^{1/3}r_1[/tex]

[tex]I_2 = 6^{2/3}I_1[/tex]
 
dnt said:
angular momentum is conserved.

and rotational inertia increases as the star expands, hence the angular velocity will go down to conserve angular momentum (L=Iw), right?

and if the volume goes up by 6 times, it means the radius went up by ~1.8 times.

do i then square that value because I=mr^2?

which means the inertia went up by (1.8)^2 = 3.3 and therefore the angular velocity (w) went down by 3.3 to compensate for that? am i understanding this correctly?
Double check your formula for moment of inertia of a solid sphere. You used the basic formula for a point mass or ring. You can derive the formula for a sphere yourself, or look them up: moment of inertia
None the less, the difference in the formulas is a constant, so it doesn't change the proportions. You'll get the same ratio either way.
 

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